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A history of Greek mathematics - Wilbourhall.org

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208 SUCCESSORS OF THE GREAT GEOMETERS<br />

area. Zenodorus's treatise was not confined to propositions<br />

about plane figures, but gave also the theorem that Of all<br />

solid figures the surfaces <strong>of</strong> which are equal, the sphere is<br />

greatest in solid content.<br />

We will briefly indicate Zenodorus's method <strong>of</strong> pro<strong>of</strong>. To<br />

begin with (1)<br />

; let ABC, DEFhe equilateral and equiangular<br />

polygons <strong>of</strong> the same perimeter, DEF having more angles<br />

than ABC. Let G, H be the centres <strong>of</strong> the circumscribing<br />

circles, GK, HL the perpendiculars from G, H to the sides<br />

AB, DE, so that K, L bisect those sides.<br />

the<br />

AM<br />

Since the perimeters are equal, AB > DE, and AK > DL.<br />

Make KM equal to DL and join GM.<br />

Since AB is the same fraction <strong>of</strong> the perimeter that the<br />

angle A GB is <strong>of</strong> four right angles, and DE is the same fraction<br />

<strong>of</strong> the same perimeter that the angle J)HE is <strong>of</strong> four right<br />

angles, it follows that<br />

that is, AK :<br />

But<br />

AB:DE=lAGB:lDHE,<br />

LAGK-.L DHL.<br />

MK=<br />

AK :MK > lAGK:l MGK<br />

(this is easily proved in a lemma following by the usual<br />

method <strong>of</strong> drawing an arc <strong>of</strong> a circle with G as centre and GM<br />

as radius cutting GA and GK produced.<br />

The proposition is <strong>of</strong>.<br />

course equivalent to tan a/ tan /S > x/fi, where \tt > a > /?).<br />

Therefore<br />

and consequently<br />

Z MGK > Z DHL,<br />

Z GMK < Z HDL.<br />

Make the angle NMK equal to the angle HDL, so that MN<br />

meets KG produced in N.

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