31.10.2014 Views

A history of Greek mathematics - Wilbourhall.org

A history of Greek mathematics - Wilbourhall.org

A history of Greek mathematics - Wilbourhall.org

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

ON THE SPHERE AND CYLINDER, I 39<br />

whence, adding antecedents and consequents, we have<br />

(Fig. 1) (BB' + 00'+... + EE') :<br />

A A' = A'B : BA,<br />

(Prop. 21)<br />

(Fig. 2) {BR + CC+...+ \PP') :AM=A'B:BA. (Prop. 2 2)<br />

When we make the polygon revolve about A A', the surface<br />

<strong>of</strong> the inscribed figure<br />

so obtained is made up <strong>of</strong> the surfaces<br />

<strong>of</strong> cones and frusta <strong>of</strong> cones; Prop. 14 has proved that the<br />

BF,<br />

.<br />

surface <strong>of</strong> the cone ABB' is what we should write tt . AB<br />

and Prop. 16 has proved that the surface <strong>of</strong> the frustum<br />

BOC'B' is tt.BC(BF+GG). It follows that, since AB =<br />

BG = . . , .<br />

the surface <strong>of</strong> the inscribed solid is<br />

tt .AB {%BW + ^(BB' + GC')+ ...},<br />

that is, tt . AB<br />

(BB' + 00'+... + EE') (Fig. 1), (Prop. 24)<br />

or tt.AB (BB' + CC+...+ ±PP') (Fig. 2). (Prop. 35)<br />

Hence, from above, the surface <strong>of</strong> the inscribed solid is<br />

n . A'B . AA' or tt . A'B .AM, and is therefore less than<br />

7T . AA' 2 (Prop. 25) or tt . A'A . AM,<br />

that is, tt . AP 2 (Prop. 37).<br />

Similar propositions with regard to surfaces formed by the<br />

revolution about AA' <strong>of</strong> regular circumscribed solids prove<br />

that their surfaces are greater than it. A A' 2, and tt .AP 2<br />

respectively (Props. 28-30 and Props. 39-40). The case <strong>of</strong> the<br />

segment is more complicated because the circumscribed polygon<br />

with its sides parallel to AB, BG ... DP circumscribes<br />

the sector POP'. Consequently, if the segment is less than a<br />

semicircle, as GAG', the base <strong>of</strong> the circumscribed polygon<br />

(cc')<br />

is on the side <strong>of</strong> GC' towards A, and therefore the circumscribed<br />

polygon leaves over a small strip <strong>of</strong> the inscribed.<br />

This<br />

complication is dealt with in Props. 39-40. Having then<br />

arrived at circumscribed and inscribed figures with surfaces<br />

greater and less than tt. AA' 2 and tt. AP 2 respectively, and<br />

having proved (Props. 32, 41) that the surfaces <strong>of</strong> the circumscribed<br />

and inscribed figures are to one another in the duplicate<br />

ratio <strong>of</strong> their sides, Archimedes proceeds to prove formally, by<br />

the method <strong>of</strong> exhaustion, that the surfaces <strong>of</strong> the sphere and<br />

segment are equal to these circles respectively (Props. 33 and<br />

42); tt .AA' 2 is <strong>of</strong> course equal to four times the great circle<br />

<strong>of</strong> the sphere. The segment is, for convenience, taken to be

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!