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A history of Greek mathematics - Wilbourhall.org

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368 PAPPUS OF ALEXANDRIA<br />

the other, i.e. it is shown that broken lines, consisting <strong>of</strong><br />

several straight lines, can be drawn with two points on the<br />

base <strong>of</strong> a triangle or parallelogram as extremities, and <strong>of</strong><br />

greater total length than the remaining two sides <strong>of</strong> the<br />

triangle or three sides <strong>of</strong> the parallelogram.<br />

Props. 40-2 show that triangles or parallelograms can be<br />

constructed with sides respectively greater than those <strong>of</strong> a given<br />

triangle or parallelogram but having a less area.<br />

Section (4). The inscribing <strong>of</strong> the five regular solids<br />

in a<br />

sphere.<br />

The fourth section <strong>of</strong> Book III (pp. 132-62) solves the<br />

problems <strong>of</strong> inscribing each <strong>of</strong> the five regular solids in a<br />

given sphere. After some preliminary lemmas (Props. 43-53),<br />

Pappus attacks the substantive problems (Props. 54-8), using<br />

the method <strong>of</strong> analysis followed by synthesis in the case <strong>of</strong><br />

each solid.<br />

(a) In order to inscribe a regular pyramid or tetrahedron in<br />

the sphere, he finds two circular sections equal and parallel<br />

to one another, each <strong>of</strong> which contains one <strong>of</strong> two opposite<br />

edges as its diameter.<br />

If d be the diameter <strong>of</strong> the sphere, the<br />

parallel circular sections have d' as diameter, where d 2 — \d' 2 .<br />

(b) In the case <strong>of</strong> the cube Pappus again finds two parallel<br />

circular sections with diameter df such that d = 2 ^d' 2 ;<br />

a square<br />

inscribed in one <strong>of</strong> these circles is one face <strong>of</strong> the cube and<br />

the square with sides parallel to those <strong>of</strong> the first square<br />

inscribed in the second circle is the opposite face.<br />

(c) In the case <strong>of</strong> the octahedron the same two parallel circular<br />

sections with diameter d' such that d = 2 fcT<br />

2<br />

are used; an<br />

equilateral triangle inscribed in one circle is<br />

one face, and the<br />

opposite face is an equilateral triangle inscribed in the other<br />

circle but placed in exactly the opposite way.<br />

(d)<br />

In the case <strong>of</strong> the icosahedron Pappus finds four parallel<br />

circular sections each passing through three <strong>of</strong> the vertices <strong>of</strong><br />

the icosahedron ; two <strong>of</strong> these are small circles circumscribing<br />

two opposite triangular faces respectively, and the other two<br />

circles are between these two circles, parallel to them, and<br />

equal to one another. The pairs <strong>of</strong> circles are determined in

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