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A history of Greek mathematics - Wilbourhall.org

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146 APOLLONIUS OF PERGA<br />

(2) In the case <strong>of</strong> the central conic, we have<br />

AR'UW = ACF'W - AGPE.<br />

(Apollonius here assumes what he does not proye till III. 1,<br />

namely that AGPE = ACQT. This is proved thus.<br />

We have GV: GT = GV 2 : CP<br />

therefore<br />

so that<br />

AGQV: ACQT = ACQV: AGPE,<br />

ACQT = AGPE.)<br />

Therefore AR'UW' = ACF'W' * ACQT,<br />

and it is easy to prove that in all cases<br />

Therefore R'M .<br />

AR'MF'=QTUM.<br />

MF' = QM(QT + MU).<br />

2<br />

;<br />

(I. 37, 39.)<br />

Let QL be drawn at right angles to CQ and equal to p'.<br />

Join Q'L and draw MK parallel to QL to meet Q'L in K.<br />

Draw CH parallel to Q'L to meet QL in H and MK in N.<br />

Now<br />

But QT :<br />

so that<br />

RfM: MF' = OQ:QE<br />

— QL : 2 QT, by hypothesis,<br />

MU<br />

= QH:QT.<br />

= CQ : CM = QH: MN,<br />

(QH + MN) :{QT + MU) = QH:QT<br />

= R'MiMF', from above.<br />

where i)a<br />

is the parameter <strong>of</strong> the principal ordinates and p the parameter<br />

<strong>of</strong> the ordinates to the diameter<br />

PV.<br />

If the tangent at the vertex A meets<br />

VP produced in E, and PT, the tangent<br />

at P, in 0, the proposition <strong>of</strong> Apollonius<br />

proves that<br />

But<br />

therefore<br />

Thus<br />

0P:PE = p:2PT.<br />

OP _ i<br />

PT 2<br />

=p.PE<br />

= p.AN.<br />

QV 2 : QD' 1 = PT 2 : PN<br />

= p<br />

.<br />

2 , by similar triangles,<br />

AN:p u<br />

. AN

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