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A history of Greek mathematics - Wilbourhall.org

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'<br />

420 PAPPUS OF ALEXANDRIA<br />

opposite sides and the two diagonals respectively, Pappus's<br />

resiilt is equivalent to<br />

AB^B'C^<br />

GA<br />

TW7M ~ C 7 A'<br />

Props. 127, 128 are particular cases in<br />

•<br />

which the transversal<br />

is parallel to a side; in Prop. 131 the transversal passes<br />

through the points <strong>of</strong> concourse <strong>of</strong> opposite sides, and the<br />

result is equivalent to the fact that the two diagonals divide<br />

into proportional parts the straight line joining the points <strong>of</strong><br />

concourse <strong>of</strong> opposite sides; Prop. 132 is the particular case<br />

<strong>of</strong> Prop. 131 in which the line joining the points <strong>of</strong> concourse<br />

<strong>of</strong> opposite sides is parallel to a diagonal; in Prop. 133 the<br />

transversal passes through one only <strong>of</strong> the points <strong>of</strong> concourse<br />

<strong>of</strong> opposite sides and is parallel to a diagonal, the result being<br />

CA = 2 GB . GB\<br />

Props. 129, 136, 137, 140, 142, 145 (Lemmas 3, 10, 11, 14, 16,<br />

19) establish the equality <strong>of</strong> the anharmonic ratios which<br />

four straight lines issuing from a point determine on two<br />

transversals ; but both transversals are supposed to be drawn<br />

from the same point on one <strong>of</strong> the four straight lines.<br />

Let<br />

AB, AC, AD be cut by transversals HBGD, HEFG. It is<br />

required to prove that<br />

HE.FG HB.GD<br />

EG.EF" HD.BC'<br />

Pappus gives (Prop. 129) two methods <strong>of</strong> pro<strong>of</strong> which are<br />

practically equivalent. The following is the pro<strong>of</strong> 'by compound<br />

ratios '.<br />

Draw HK parallel to AF meeting DA and AE produced

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