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A history of Greek mathematics - Wilbourhall.org

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326 HERON OF ALEXANDRIA<br />

is given as approximately 8 — TV<br />

In Metrica I. 9, as we<br />

have seen, \/(63) is given as 1\ \ § y 1^, which was doubtless<br />

obtained from the formula (1) as<br />

The above seems to be the only classical rule which has<br />

been handed down for finding second and further approximations<br />

to the value <strong>of</strong> a surd. But, although Heron thus<br />

shows how to obtain a second approximation, namely by<br />

formula (2), he does not seem to make any direct use <strong>of</strong><br />

this method himself, and consequently the<br />

question how the<br />

approximations closer than the first which are to be found in<br />

his works were obtained still remains an open one.<br />

(y)<br />

Quadrilaterals.<br />

It is unnecessary to give in detail the methods <strong>of</strong> measuring<br />

the areas <strong>of</strong> quadrilaterals (chaps. 11-16). Heron deals with<br />

the following kinds, the parallel-trapezium (isosceles or nonisosceles),<br />

the rhombus and rhomboid, and the quadrilateral<br />

which has one angle right and in which the four sides have<br />

given lengths. Heron points out that in the rhombus or<br />

rhomboid, and in the general case <strong>of</strong> the quadrilateral, it is<br />

necessary to know a diagonal as well as the four sides. The<br />

mensuration in all the cases reduces to that <strong>of</strong> the rectangle<br />

and triangle.<br />

(8) The regular 'polygons with 3, 4, 5, 6, 7, 8, 9, 10, 11,<br />

or 12 sides.<br />

Beginning with the equilateral triangle (chap. 17), Heron<br />

proves that, if a be the side and p the perpendicular from<br />

a vertex on the opposite side, a 2 :p 2 = 4 : 3, whence<br />

a 4 :^2 a 2 = 4:3 = 16:12,<br />

so that a 4 :(AABC) 2 = 16:3,<br />

and (AABC) 2 = ^a*. In the particular case taken a — 10<br />

and A 2 = 1875, whence A = 43^ nearly.<br />

Another method is to use an approximate value for \/3 in<br />

the formula Vs . a 2 /4. This is what is done in the Geometrica<br />

14 (10, Heib.), where we are told that the area is (§ + i<br />

1<br />

o)^2<br />

;

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