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A history of Greek mathematics - Wilbourhall.org

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408 PAPPUS OF ALEXANDRIA<br />

VI. Props. 37, 38.<br />

If AB:BC = AD 2 : DC<br />

than AD, then<br />

2 ,- whether AB be "greater or less<br />

AB.BG = BD 2 .<br />

\E in the figure is a point such that ED = CD.]<br />

A (E) D C B<br />

i 1 1 1<br />

A C B P (f)<br />

i<br />

i<br />

The algebraical equivalent is: If - = .,"" L t<br />

then ac — b 2 .<br />

These lemmas are subsidiary to the next (Props. 39, 40),<br />

being used in the first pro<strong>of</strong>s <strong>of</strong> them.<br />

Props. 39, 40 prove the following:<br />

If AGDEB be a straight line, and if<br />

BA . AE: BD.DE = AC 2 : CD<br />

2 ,<br />

2 ;<br />

then AB.BD:AE.ED = BG 2 : GE<br />

if, again, AG .CB.AE . EB = CD 2 :DE 2 ,<br />

then EA .AC:CB.BE = AD 2 : DB<br />

2 .<br />

If AB = a, BG = b, BD = c, BE— d, the algebraic equivalents<br />

are the following.<br />

a (a-d) (a-b) 2 ac b 2<br />

c(c-d)<br />

'<br />

'<br />

(b-cf '<br />

(a-d) (c-d) " (6-d) 2 '<br />

, .„ (a — b)b (b —<br />

2 c) .. (a —<br />

2<br />

c£)( then<br />

(a — d)d (c — df bd c 2<br />

VII. Props. 41, 42, 43.<br />

If AD.DC=BD.DE, suppose that in Figures (1) and (2)<br />

0) O A $ D E B<br />

(2) A E D C B°<br />

" : 1 1<br />

(3) A E B C ,p<br />

k = AE+GB, and in Figure (3) k = AE-BG, then<br />

k.AD = k.GD = BA.AEt BG.GE, k.BD = AB.BC,<br />

k.DE=AE.EC.

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