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A history of Greek mathematics - Wilbourhall.org

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312 HERON OF ALEXANDRIA<br />

triangle which is constructed to be constructed on the same<br />

side <strong>of</strong> the common side as the given triangle is.<br />

A third class (c) is that which avoids reductio ad absurdum,<br />

e.g. a direct pro<strong>of</strong> <strong>of</strong> I. 19 (for which he requires and gives<br />

a preliminary lemma) and <strong>of</strong> I. 25.<br />

(4) Heron supplies certain converses <strong>of</strong> Euclid's propositions<br />

e.g. <strong>of</strong> II. 12, 13 and VIII. 27.<br />

(5) A few additions to, and extensions <strong>of</strong>, Euclid's propositions<br />

are also found. Some are unimportant, e. g. the construction<br />

<strong>of</strong> isosceles and scalene triangles in a note on I. 1 and the<br />

construction <strong>of</strong> two tangents in III. 17. The most important<br />

extension is that <strong>of</strong> III. 20 to the case where the angle at the<br />

circumference is greater than a right angle, which gives an<br />

easy way <strong>of</strong> proving the theorem <strong>of</strong> III. 22. Interesting also<br />

are the notes on I. 37 (on I. 24 in Proclus), where Heron<br />

proves that two triangles with two sides <strong>of</strong> the one equal<br />

to two sides <strong>of</strong> the other and with the included angles supplementary<br />

are equal in area, and compares the areas where the<br />

sum <strong>of</strong> the included angles (one being supposed greater than<br />

the other) is less or greater than two right angles, and on I. 47,<br />

where there is a pro<strong>of</strong> (depending on preliminary lemmas) <strong>of</strong><br />

the fact that, in the figure <strong>of</strong> Euclid's proposition (see next<br />

page), the straight lines AL, BG, GE meet in a point. This<br />

last pro<strong>of</strong> is worth giving.<br />

First come the lemmas.<br />

(1) If in a triangle ABG a straight line DE be drawn<br />

parallel to the base BG cutting the sides AB, AC or those<br />

sides produced in D, E, and if F be the<br />

middle point <strong>of</strong> BG, then the straight line<br />

AF (produced if necessary) will also bisect<br />

DE.<br />

(HK is drawn through A parallel to<br />

DE, and HDL, REM through D, E parallel<br />

to AF meeting the base in L, M respectively.<br />

Then the triangles ABF, AFC<br />

between the same parallels are equal. So are the triangles<br />

DBF, EFC. Therefore the differences, the triangles ADF,<br />

AEF, are equal and so therefore are the parallelograms HF,<br />

KF. Therefore LF = FM, or DG = GE.)<br />

(2) is the converse <strong>of</strong> Eucl. 1. 43. If a parallelogram is

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