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A history of Greek mathematics - Wilbourhall.org

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!<br />

;<br />

434 PAPPUS OF ALEXANDRIA<br />

about FL as if L were the fulcrum <strong>of</strong> a lever. Now the<br />

weight A acts vertically downwards along a straight line<br />

through E. To balance it, Pappus supposes a weight B<br />

attached with its centre <strong>of</strong> gravity at G.<br />

Then<br />

A:B=GF:EF<br />

= (EL-EF):EF<br />

[= (l-sin0):sin0,<br />

where IKMN = $];<br />

and, since LKMN is given, the ratio EF: EL,<br />

and therefore the ratio (EL-EF) :<br />

given ;<br />

thus B is found.<br />

EF, is<br />

Now, says Pappus, if D is the force which will move B<br />

along a horizontal plane, as C is the force which will move<br />

A along a horizontal plane, the sum <strong>of</strong> C and D will be the<br />

force required to move the sphere upwards on the inclined<br />

plane. He takes the particular case where 6 = 60°. Then<br />

sin 6 is approximately y§£ (he evidently uses \ ff for \ \/3),<br />

.<br />

and A\B— 16:104.<br />

Suppose, for example, that A = 200 talents; then B is 1300<br />

talents. Suppose further that C is 40 man-power ; then, since<br />

D:C = B: A, D = 260 man-power ; and it will take D + C, or<br />

300 man-power, to move the weight up the plane<br />

Prop. 10 gives, from Heron's Barulcus, the machine consisting<br />

<strong>of</strong> a pulley, interacting toothed wheels, and a spiral<br />

screw working on the last wheel and turned by a handle<br />

Pappus merely alters the proportions <strong>of</strong> the weight to the<br />

force, and <strong>of</strong> the diameter <strong>of</strong> the wheels. At the end <strong>of</strong><br />

the chapter (pp. 1070-2) he repeats his construction for the<br />

finding <strong>of</strong> two mean proportionals.<br />

Construction <strong>of</strong> a conic<br />

through Jive points.<br />

Chaps. 13-17 are more interesting, for they contain the<br />

solution <strong>of</strong> the problem <strong>of</strong> constructing a conic through five<br />

given points. The problem arises in this way. Suppose we<br />

are given a broken piece <strong>of</strong> the surface <strong>of</strong> a cylindrical column<br />

such that no portion <strong>of</strong> the circumference <strong>of</strong> either <strong>of</strong> its base

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