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A history of Greek mathematics - Wilbourhall.org

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436 PAPPUS OF ALEXANDRIA<br />

to this diameter. Then R is determined by means <strong>of</strong> the<br />

relation<br />

in this way.<br />

RG.GD.BG.GA = RE.EB:FE.EE (1)<br />

Join DB, RA, meeting EF in K, L respectively.<br />

Then, by similar triangles,<br />

RG.GD.BG.GA = (RE : EL) . (BE : EK)<br />

= RE.EB:KE.EL<br />

Therefore, by ( 1<br />

), FE.EE = KE . EL,<br />

whence EL is determined, and therefore L. The intersection<br />

<strong>of</strong> AL, BE determines R.<br />

Next, in order to find the extremities P, P /<br />

through V, W, we draw ED, RF meeting FP /<br />

in M, JS T respectively.<br />

Then, as before,<br />

<strong>of</strong> the diameter<br />

FW. WE:P'W. WP = FE.EE-.RE.ED, by the ellipse,<br />

Therefore<br />

= FW.WE-.NW.WM, by similar triangles.<br />

P' W. WP = NW. WM;<br />

and similarly we can find the value <strong>of</strong> P'V .<br />

VP.<br />

Now, says Pappus, since P'W. WP and P'V.VP are given<br />

areas and the points V, W are given, P, P' are given. His<br />

determination <strong>of</strong> P, P' amounts (Prop. 14 following) to an<br />

elimination <strong>of</strong> one <strong>of</strong> the points and the finding <strong>of</strong> the other<br />

by means <strong>of</strong> an equation <strong>of</strong> the second degree.<br />

Take two points Q, Q' on the diameter such that<br />

P'V.VP=WV.VQ,<br />

(a)<br />

P f W.WP = VW.WQ'\ (13)<br />

Q,<br />

Q' are thus known, while P, P' remain to be found.<br />

By (a)<br />

P'V: VW= QV: VP,<br />

W whence P' : VW= PQ : P V.<br />

Therefore, by means <strong>of</strong> (/?),<br />

PQ:PV=Q / W:WP,

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