31.10.2014 Views

A history of Greek mathematics - Wilbourhall.org

A history of Greek mathematics - Wilbourhall.org

A history of Greek mathematics - Wilbourhall.org

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

;<br />

144 APOLLONIUS OF PERGA<br />

Therefore RUW, CPE, CFW are the halves <strong>of</strong> parallelograms<br />

related as in the lemma<br />

therefore<br />

ARUW = A CFW - A CPE.<br />

The same property with reference to the diameter secondary<br />

to CPV is proved in I. 45.<br />

It is interesting to note the exact significance <strong>of</strong> the property<br />

thus proved for the central conic. The proposition, which is<br />

the foundation <strong>of</strong> Apollonius's method <strong>of</strong> transformation <strong>of</strong><br />

coordinates, amounts to this. If OP, CQ are fixed semidiameters<br />

and R a variable point, the area <strong>of</strong> the quadrilateral<br />

GFRU is constant for all positions <strong>of</strong> R on the conic.<br />

Suppose<br />

now that CP, CQ are taken as axes <strong>of</strong> x and y respectively.<br />

If we draw RX parallel to CQ to meet CP and RY parallel to<br />

CP to meet CQ, the proposition asserts that (subject to the<br />

proper convention as to sign)<br />

ARYF+CJCXRY+ARXU = (const).<br />

But since RX, RY, RF, RU are in fixed directions,<br />

ARYF varies as RY 2 or x 2 ,<br />

C3CXRY<br />

and ARXU as RX 2<br />

as RX .<br />

or if.<br />

Hence, if x, y are the coordinates <strong>of</strong> R,<br />

ocx 2 + fixy + yy<br />

2 — A,<br />

RY<br />

or xy,<br />

which is the Cartesian equation <strong>of</strong> the conic referred to the<br />

centre as origin and any two diameters as axes.<br />

The properties so obtained are next used to prove that,<br />

if UR meets the curve again in R f and the diameter through<br />

Q in M, then RR' is bisected at M. (I. 46-8).<br />

Taking (1) the case <strong>of</strong> the parabola, we have,<br />

and<br />

By subtraction,<br />

whence<br />

ARUW=EJEW,<br />

AR'UW'=CJEW'.<br />

(RWW'R) = CJF'W,<br />

and, since the triangles are similar,<br />

ARFM = AR'F'M,<br />

RM — R'M.<br />

The same result is easily obtained for the central conic.<br />

It follows that EQ produced in the case <strong>of</strong> the parabola,

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!