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A history of Greek mathematics - Wilbourhall.org

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HYPSICLES 217<br />

II. If Oj, a 2<br />

... a n<br />

... a 2 «-i<br />

is a descending arithmetical progression<br />

<strong>of</strong> 2n—l terms with 8 as common difference and a n<br />

is the middle term, then<br />

a 1<br />

+ « 2<br />

+...+a 2n _ 1<br />

= (27i-l)a n<br />

.<br />

III. If a 1}<br />

a 2<br />

...a n<br />

, a n+1 ...a 2n is a descending arithmetical<br />

progression <strong>of</strong> 2n terms, then<br />

a x<br />

+ a 2<br />

+ .<br />

. . +<br />

a 2 n<br />

= w (a x<br />

+ a 2 n ) = n (a 2<br />

+ a 2 n _ 2 ) = .<br />

.<br />

Now let J.,<br />

= ^(a w + a n+1 ).<br />

5, G be the descending series the sum <strong>of</strong> which<br />

is 105, and D, E, F the next three terms in the same series<br />

the sum <strong>of</strong> which is 75, the common difference being 8; we<br />

then have, by (I),<br />

and 8= 3|.<br />

A + B + G-(D + E+F) = 98, or 30 = 98,<br />

Next, by (II), A + B + C =3B, or 3B = 105, and B = 35<br />

;<br />

therefore ^4, i?, (7, 2), i?, .Fare equal to 38§, 35, 31 §, 28-J, 25,<br />

21§ time-degrees respectively, which the author <strong>of</strong> the tract<br />

expresses in time-degrees and minutes as 38*20', 35*, 31*40',<br />

28* 20', 25*, 21* 40'. We have now to carry through the same<br />

procedure for each degree in each sign. If the difference<br />

between the times taken to rise by one sign and the next<br />

is 3* 20', what is the difference for each <strong>of</strong> the 30 degrees in<br />

the sign 1 We have here 30 terms followed by 30 other terms<br />

<strong>of</strong> the same descending arithmetical progression, and the<br />

formula (I) gives 3* .<br />

20' 2<br />

= (30)

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