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A history of Greek mathematics - Wilbourhall.org

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332 HERON OF ALEXANDRIA<br />

view <strong>of</strong> their surprising character, referred to Archimedes by<br />

certain writers who give the traditional account <strong>of</strong> their<br />

origin. But whether they belong to Archimedes or another,<br />

it is necessary to give a sketch <strong>of</strong> these methods as well.'<br />

The Book begins with generalities about figures all the<br />

sections <strong>of</strong> which parallel to the base are equal to the base<br />

and similarly situated, while the centres <strong>of</strong> the sections are on<br />

a straight line<br />

through the centre <strong>of</strong> the base, which may be<br />

either obliquely inclined or perpendicular to the base ;<br />

whether<br />

the said straight line (' the axis ') is or is not perpendicular to<br />

the base, the volume is equal to the product <strong>of</strong> the area <strong>of</strong> the<br />

base and the perpendicular height <strong>of</strong> the top <strong>of</strong> the figure<br />

'<br />

from the base. The term height ' is thenceforward restricted<br />

to the length <strong>of</strong> the perpendicular from the top <strong>of</strong> the figure<br />

on the base.<br />

(a) Cone, cylinder, parallelepiped (prism), pyramid, and<br />

II.<br />

frustum.<br />

1-7 deal with a cone, a cylinder, a 'parallelepiped' (the<br />

base <strong>of</strong> which is not restricted to the parallelogram but is in<br />

the illustration given a regular hexagon, so that the figure is<br />

more properly a prism with polygonal bases), a triangular<br />

prism, a pyramid with base <strong>of</strong> any form, a frustum <strong>of</strong> a<br />

triangular pyramid ;<br />

the figures are in general oblique,<br />

(f3) Wedge-shaped solid (ficDfjLiorKos or crcprjvio-Kos).<br />

II. 8 is a case which is perhaps worth giving. It is that <strong>of</strong><br />

a rectilineal solid, the base <strong>of</strong> which is a rectangle ABCD and<br />

has opposite to it another rectangle EFGH, the sides <strong>of</strong> which<br />

are respectively parallel but not necessarily proportional to<br />

those <strong>of</strong> ABCD. Take AK equal to EF, and BL equal to FG.<br />

Bisect BK, CL in V, W, and draw KRPU, VQOM parallel to<br />

AD, and LQRN, WOPT parallel to AB. Join FK, GR, LG,<br />

GU, BK<br />

Then the solid is divided into (1) the parallelepiped with<br />

AR, EG as oppqsite faces, (2) the prism with KL as base and<br />

FG as the opposite edge, (3) the prism with NU as base and<br />

GH as opposite edge, and (4) the pyramid with RLGU as base<br />

and G as vertex. Let h be the<br />

'<br />

height ' <strong>of</strong> the figure. Now

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