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A history of Greek mathematics - Wilbourhall.org

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380 PAPPUS OF ALEXANDRIA<br />

principii. Its use for squaring the circle is attributed to<br />

Dinostratus and Nicomedes. The whole substance <strong>of</strong> this<br />

subsection is given above (vol. i, pp. 226-30).<br />

Tivo constructions for the quadratrix by means <strong>of</strong><br />

'<br />

surface-loci '.<br />

In the next chapters (chaps. 33, 34, Props. 28, 29) Pappus<br />

gives two alternative ways <strong>of</strong> producing the quadratrix by<br />

'<br />

means <strong>of</strong> surface-loci ', for which he claims the merit that<br />

they are geometrical rather than too mechanical ' ' as the<br />

traditional method (<strong>of</strong> Hippias) was.<br />

(1) The first method uses a cylindrical helix thus.<br />

Let ABC be a quadrant <strong>of</strong> a circle with centre B, and<br />

let BD be any radius. Suppose<br />

that EF, drawn from a point E<br />

on the radius BD perpendicular<br />

to BG, is (for all such radii) in<br />

a given ratio to the arc DC.<br />

'<br />

I say ', says Pappus, ' that the<br />

locus <strong>of</strong> E is a certain curve.'<br />

Suppose a right cylinder<br />

erected from the quadrant and<br />

a cylindrical helix GGH drawn<br />

upon its surface. Let DH be<br />

the generator <strong>of</strong> this cylinder through D, meeting the<br />

helix<br />

in H. Draw BL, EI at right angles to the plane <strong>of</strong> the<br />

quadrant, and draw HIL parallel to BD.<br />

Now, by the property <strong>of</strong> the helix, EI(=DH) is to the<br />

arc GD in a given ratio. Also EF : (arc CD) = a given ratio.<br />

Therefore the ratio EF : EI is given, And since EF, EI are<br />

given in position, FI is given in position. But FI is perpendicular<br />

to BG. Therefore FI is in a plane given in position,<br />

and so therefore is /.<br />

But i" is also on a certain surface described by the line LH<br />

,<br />

which moves always parallel to the plane ABC, with one<br />

extremity L on BL and the other extremity H on the helix.<br />

Therefore / lies on the intersection <strong>of</strong> this surface with the<br />

plane through FI

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