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A history of Greek mathematics - Wilbourhall.org

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—<br />

,<br />

'<br />

MENELAUS'S SPHAERICA 269<br />

It follows at once (Prop. 4) that, if AM, A'M' are great<br />

circles drawn perpendicular to the bases BG, B'C <strong>of</strong> two<br />

spherical triangles ABC, A'B'C in which B = B',C — G',<br />

sin BM sin MC / . ,<br />

,<br />

—<br />

sin B'M'<br />

, ,<br />

tan<br />

AM \<br />

^i^r, — ~— TF77T* I<br />

since both are equal to jttF' )'<br />

smM'C'K<br />

III. 5 proves that, if<br />

*<br />

tan A'M'}<br />

there are two spherical triangles ABC,<br />

P<br />

P'<br />

A'B'C right-angled at A, A' and such that C—C, while 6<br />

and 6' are less than 90°,<br />

sin (a + b) _ sin (a' + &')<br />

sin (a — b)<br />

from which we may deduce 1<br />

sin (a/ — b')<br />

the formula<br />

sin (a + b) 1 + cos 6 T<br />

sin (a — b)<br />

~" 1 — cos C<br />

which is equivalent to tan b = tan a cos C.<br />

(y) Anharmonic property <strong>of</strong> four great circles through<br />

one point.<br />

But more important than the above result is<br />

the pro<strong>of</strong> assumes as known the anharmonic<br />

property <strong>of</strong> four great circles<br />

drawn from a point on a sphere in relation<br />

to any great circle intersecting them<br />

all,<br />

viz. that, if ABCD, A'B'G'D' be two<br />

transversals,<br />

sin AD sin BC sinA'D' sin B'C<br />

sin DG<br />

'<br />

sin AB " sin B'C' '<br />

sin A'B'<br />

the fact that<br />

* Braunmiihl, op. cit. i, p. 18; Bjornbo, p. 96.

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