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A history of Greek mathematics - Wilbourhall.org

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1<br />

482 DIOPHANTUS OF ALEXANDRIA<br />

hypotenuse. The method is this. Form two right-angled<br />

triangles from (a, b) and (c, d) respectively, by which Diophantus<br />

means, form the right-angled triangles<br />

(a 2 + b 2 , a 2 -b 2 , 2ab) and (c 2 + d 2 , c 2 -d 2 , 2cd).<br />

Multiply all the sides in each triangle by the hypotenuse <strong>of</strong><br />

the other; we have then two rational right-angled triangles<br />

with the same hypotenuse (a 2 + b 2 ) (c 2 + d 2 ).<br />

Two others are furnished by the formula above; for we<br />

have only to form two right-angled triangles ' ' from (ac + bd,<br />

ad — be) and from (ac — bd, ad + be) respectively. The method<br />

fails if certain relations hold between a, b, c, d. They must<br />

not be such that one number <strong>of</strong> either pair vanishes, i.e.<br />

such<br />

that ad = be or ac = bd, or such that the numbers in either<br />

pair are equal to one another, for then the triangles are<br />

illusory.<br />

In the case taken by Diophantus a 2 + b 2 = 2 2 +<br />

2<br />

= 5,<br />

c 2 + d 2 = 3 2 + 2 2 = 1 3, and the four right-angled triangles are<br />

(65, 52, 39), (65, 60, 25), (65, 63, 16) and (65, 56, 33).<br />

On this proposition Fermat has a long and interesting note<br />

as to the number <strong>of</strong> ways in which a prime number <strong>of</strong> the<br />

form 4 n + 1 and its powers can be (a) the hypotenuse <strong>of</strong><br />

a rational right-angled triangle, (b) the sum <strong>of</strong> two squares.<br />

He also extends theorem (3) above : If a prime number which<br />

'<br />

is the sum <strong>of</strong> two squares be multiplied by another prime<br />

number which is also the sum <strong>of</strong> two squares, the product<br />

will be the sum <strong>of</strong> two squares in two ways ; if the first prime<br />

be multiplied by the square <strong>of</strong> the second, the product will be<br />

the sum <strong>of</strong> two squares in three ways ; the product <strong>of</strong> the first<br />

and the cube <strong>of</strong> the second will be the sum <strong>of</strong> two squares<br />

in four ways, and so on ad infinitum'<br />

Although the hypotenuses selected by Diophantus, 5 and 13,<br />

are prime numbers <strong>of</strong> the form 4 n + 1 , it is unlikely that he<br />

was aware that prime numbers <strong>of</strong> the form 4 n + 1 and<br />

numbers arising from the multiplication <strong>of</strong> such numbers are<br />

the only classes <strong>of</strong> numbers which are always the sum <strong>of</strong> two<br />

squares ;<br />

this was first proved by Euler.<br />

(4) More remarkable is a condition <strong>of</strong> possibility <strong>of</strong> solution<br />

prefixed to V. 9, 'To divide 1 into two parts such that, if

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