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A history of Greek mathematics - Wilbourhall.org

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,<br />

METHOD OF APPROXIMATION TO LIMITS 479<br />

therefore y = 2, and 1 /x 2 = 3%<br />

; and Sj + ^g = ±jg-, a square.<br />

We have now, says Diophantus, to divide 10 into three<br />

squares with sides as near as may be to -^.<br />

Now 10 = 9 + 1 =3 2 + (f)<br />

2<br />

+ (f)<br />

2.<br />

Bringing 3, f-<br />

,<br />

90 18 24 onrl 55<br />

30 > 3~0> 3~0 d/11U 3 '<br />

f and ^ to a common denominator, we have<br />

and 3 > || by §f<br />

5 ^ 3 u J 30'<br />

5" < "30 °y 30'<br />

If now we took 3 — §J, f + |J ,<br />

§ + f§ as the sides <strong>of</strong> squares,<br />

the sum <strong>of</strong> the squares would be 3 (V) 2 or " 3 3-<br />

3%<br />

><br />

which is > 10.<br />

Accordingly we assume as the sides 3 — 35 #, § + 3 7 &•, f + 3 1 #,<br />

where a?<br />

must therefore be not exactly 3V but near it.<br />

Solving (3-35 l£) 2 + (! + 37£) 2 + (f<br />

+ 31^) 2 = 10,<br />

or 10-116^ + 3555^2 = 10,<br />

we find x = ^A 5<br />

thus the sides <strong>of</strong> the required squares are -VtiN ^ttt* VttS<br />

the squares themselves are WA%<br />

4<br />

iS T5r£rr> VSfiflRtf-<br />

Other instances <strong>of</strong> the application <strong>of</strong> the method will be<br />

found in V. 10, 12, 13, 14.<br />

Porisms and propositions in the Theory <strong>of</strong> Numbers.<br />

I. Three propositions are quoted as occurring in the Porisms<br />

(' We have it in the Porisms that ...'); and some other propositions<br />

assumed without pro<strong>of</strong> may very likely have come<br />

from the same collection. The three propositions from the<br />

Porisms are to the following effect.<br />

1. If a is a given number and x, y numbers such that<br />

x + a = m 2 , y + a = n 2 , then, if xy + a is also a square, m and n<br />

differ by unity (V. 3).<br />

[From the first two equations we obtain easily<br />

xy + a = m 2 n 2 — a (m 2 + n 2 — 1) + a 2 ,<br />

and this is obviously a square if m 2 + n 2 — 1 = 2 mn, or<br />

m — n = ±1-]

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