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A history of Greek mathematics - Wilbourhall.org

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HIPPARCHUS 259<br />

in his Commentary, he used the formulae <strong>of</strong> spherical trigonometry<br />

to get his results. In the particular case where it is<br />

required to find the time in which a star <strong>of</strong> 27-§° northern<br />

declination describes, in the latitude <strong>of</strong><br />

Rhodes, the portion <strong>of</strong><br />

its arc above the horizon, Hipparchus must have used the<br />

equivalent <strong>of</strong> the formula in the solution <strong>of</strong> a right-angled<br />

spherical triangle, tan b = cos A tan c, where C is the right<br />

angle. Whether, like Ptolemy, Hipparchus obtained the<br />

formulae, such as this one, which he used from different<br />

applications <strong>of</strong><br />

the one general theorem (Menelaus's theorem)<br />

it is not possible to say. There was <strong>of</strong> course no difficulty<br />

in calculating the tangent or other trigonometrical function<br />

<strong>of</strong> an angle if only a table <strong>of</strong> sines was given ; for Hipparchus<br />

and Ptolemy were both aware <strong>of</strong> the fact expressed by<br />

sin 2 a + cos 2 a = 1<br />

or, as they would have written it,<br />

(crd. 2a) 2 + {crd. (180°-2a)} 2 = 4r 2 ,<br />

where (crd. 2 a) means the chord subtending an arc 2 a, and r<br />

is the radius, <strong>of</strong> the circle <strong>of</strong> reference.<br />

Table <strong>of</strong> Chords.<br />

We have no details <strong>of</strong> Hipparchus's Table <strong>of</strong> Chords sufficient<br />

to enable us to compare it with Ptolemy's, which goes<br />

by half-degrees, beginning with angles <strong>of</strong> |°, 1°, l-§°, and so<br />

on. But Heron 1 in his Metrica says that 'it is proved in the<br />

books about chords in a circle ' that, if « 9<br />

and a n are the sides<br />

<strong>of</strong> a regular enneagon (9 -sided figure) and hendecagon (1 1 -sided<br />

figure) inscribed in a circle <strong>of</strong> diameter d, then (1) a 9<br />

= ^d,<br />

(2) a u = £gd very nearly, which means that sin 20° was<br />

taken as equal to 0-3333 ... (Ptolemy's table makes it<br />

Rn( 20 "** fin + fin?)' S0 ^a^ ^e ^rs^ a PP roxmiati°n is §), and<br />

sin T X T<br />

.<br />

180° or sin 16° 21' 49" was made equal to 0-28 (this corresponds<br />

to the chord subtending an angle <strong>of</strong> 32° 43' 38",nearly<br />

half-way between 32J° and 33°, and the mean between the two<br />

1 /lt> 54 55 \<br />

chords subtending the latter angles gives —<br />

(<br />

+ — H |<br />

as<br />

the required sine, while eV (<br />

16A) = Iff, which only differs<br />

1<br />

Heron, Metrica, i. 22, 24, pp. 58. 19 and 62. 17.<br />

s2

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