The Design of Diagnostic Medical Facilities where ... - ResearchGate
The Design of Diagnostic Medical Facilities where ... - ResearchGate
The Design of Diagnostic Medical Facilities where ... - ResearchGate
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Example 3: X‐ray room window (BIR method)<br />
<strong>The</strong> general radiographic room is located on the first floor. <strong>The</strong>re is a window in the external wall, which is<br />
at a height much greater than 2 m from the outside ground. <strong>The</strong> distance from the patient table to the<br />
window is 2 m. An occupant works at the window <strong>of</strong> an <strong>of</strong>fice across the courtyard at a distance <strong>of</strong> 8 m from<br />
the window <strong>of</strong> the X-ray room.<br />
<strong>The</strong> weekly workload for the room has been obtained from the Radiology Information System (RIS) and<br />
found to be 1000 Gy cm 2 for 300 examinations, with an average X‐ray beam energy <strong>of</strong> 100 kVp.<br />
What shielding is required for this window<br />
<strong>The</strong>re is no vertical bucky in the room and lateral exposures will not be directed towards the window in this<br />
instance, so only scattered radiation needs to be considered.<br />
<strong>The</strong> annual dose constraint, D c<br />
= 0.3 mSv<br />
Occupancy in <strong>of</strong>fice across courtyard, T = 100%<br />
Distance from patient on table to<br />
occupant in the <strong>of</strong>fice, d<br />
= 10 m<br />
Average weekly DAP = 1000 Gy cm 2<br />
Scatter factor at 1 m, S max<br />
= [(0.031 x kVp) + 2.5] μGy (Gy cm 2 ) -1 (Equation 5.3)<br />
= 5.6 μGy (Gy cm 2 ) -1<br />
<strong>The</strong> incident kerma,<br />
S<br />
max<br />
× DAP<br />
K<br />
inc<br />
=<br />
d<br />
2<br />
(Equation 5.4)<br />
5.6×<br />
1000<br />
= 56μGy = 0.056 mGy ≡ 0.056 mSv<br />
10<br />
K<br />
inc<br />
=<br />
2<br />
Max. transmission,<br />
B<br />
=<br />
K<br />
inc<br />
D<br />
c<br />
× T × 52<br />
= 0.3 mSv<br />
0.056 mSv × 1×<br />
52<br />
= 0.1030<br />
From equation 5.6 for the transmission through lead and concrete, 0.3 mm lead or 26 mm concrete is<br />
needed to shield the window (see also Appendix C) (neglecting any attenuation in the glass<br />
window).<br />
Window shielding is therefore required in this room even though the window is located at a height <strong>of</strong><br />
greater than 2 m from the outside ground. Shielding may be provided as outlined in Section 6.3.4.<br />
Should there be a requirement to direct lateral exposures towards the window then the shielding<br />
requirement will be increased.<br />
If there are two adjacent X‐ray rooms with external windows facing into the courtyard then the<br />
combined effect <strong>of</strong> both rooms on the <strong>of</strong>fice will have to be considered.<br />
<strong>The</strong> <strong>Design</strong> <strong>of</strong> <strong>Diagnostic</strong> <strong>Medical</strong> <strong>Facilities</strong> <strong>where</strong> Ionising Radiation is used 69