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The Design of Diagnostic Medical Facilities where ... - ResearchGate

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Example 4: Dental X‐ray room (BIR method)<br />

An intra-oral dental X‐ray facility may require shielding from both primary and secondary radiation. <strong>The</strong><br />

primary beam should be intercepted by the patient, resulting in a transmission no greater than 2 μGy per film<br />

(BIR, 2000). In this facility the distance from the wall to the nearest occupant in the adjoining surgery is 0.3<br />

m, and the distance from the patient’s head/X‐ray tube head to the wall is 0.7 m. <strong>The</strong> weekly workload for<br />

the X‐ray room is 100 intra-oral exposures.<br />

Assuming 100% occupancy in the adjoining surgery what shielding is required in the common partition<br />

wall<br />

BIR advise that for intra-oral exposures the weighted average <strong>of</strong> primary plus scattered radiation dose at 1 m<br />

is 1 μGy per film (BIR, 2000).<br />

<strong>The</strong> annual dose constraint, D c<br />

= 0.3 mSv<br />

Occupancy, T, in adjoining surgery = 100%<br />

Distance, d, from patient to occupant = 1.0 m<br />

Average scatter dose per film at 1 m = 1 μGy<br />

Weekly scatter based on 100 films = 100 μGy at 1 m<br />

<strong>The</strong> incident kerma, K inc<br />

= 100 μGy/week<br />

= 0.1 mGy/week ≡ 0.1 mSv/week<br />

Max. transmission, B =<br />

K<br />

inc<br />

D<br />

c<br />

0.3 mSv<br />

=<br />

× T × 52 0.1 mSv × 1×<br />

52<br />

= 0.0577<br />

From equation 5.6 for the transmission through lead, 0.2 mm lead will provide the shielding needed<br />

at 70 kVp (see also Appendix C). In practice, Code 3 (1.32 mm) lead would provide adequate protection<br />

and allow for increases in workload.<br />

70<br />

<strong>The</strong> <strong>Design</strong> <strong>of</strong> <strong>Diagnostic</strong> <strong>Medical</strong> <strong>Facilities</strong> <strong>where</strong> Ionising Radiation is used

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