The Design of Diagnostic Medical Facilities where ... - ResearchGate
The Design of Diagnostic Medical Facilities where ... - ResearchGate
The Design of Diagnostic Medical Facilities where ... - ResearchGate
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5.3.2 Nuclear medicine shielding calculation examples<br />
Example 5: Shielding required for gamma camera room<br />
A gamma camera room is adjacent to the reception area. 60 patients per week are scanned using a 99m Tc<br />
bone scanning agent with an administered activity <strong>of</strong> 600 MBq. Patients are scanned two hours post<br />
administration and scanning time per patient is 30 minutes. <strong>The</strong> distance from the patient to a person in the<br />
adjoining <strong>of</strong>fice is 3 m.<br />
What shielding is required for the wall between the camera room and the reception<br />
<strong>The</strong> dose from a single patient at the point <strong>of</strong> interest is given by equation 5.7:<br />
F<br />
D(t) = D(0)<br />
.<br />
× t × R<br />
t<br />
×<br />
d<br />
<strong>where</strong> Ḋ(0) is the product <strong>of</strong> the dose rate constant for the patient, having been administered 99m Tc and<br />
the activity administered (MBq), t is the scanning time, and F u<br />
and R t<br />
are the decay factor prior to<br />
scanning and the dose reduction factor during scanning respectively.<br />
u<br />
2<br />
For a workload <strong>of</strong> N w<br />
patients per week, the annual dose at a distance d from the patient is:<br />
.<br />
F<br />
D(t<br />
a)<br />
= N<br />
w<br />
× 52×<br />
D(0) × t × R<br />
t<br />
×<br />
d<br />
Values for the dose rate constant for the patient administered 99m Tc , R t<br />
and F u<br />
are given in Section 5.2.8<br />
as 0.0075 μSv m 2 /MBqh, 0.97 and 0.79.<br />
u<br />
2<br />
Thus:<br />
D(t a<br />
) = 60 x 52 x 0.0075 μSv m 2 /MBqh x 600 MBq x 0.5 h x 0.97 x<br />
= 598 μSv = 0.598 mSv<br />
0.79<br />
9<br />
For an occupancy factor <strong>of</strong> 1.0, and a dose constraint <strong>of</strong> 0.3 mSv, the transmission is<br />
0.3 mSv<br />
B =<br />
= 0.50<br />
0.598 mSv × 1<br />
To reduce the transmission to 50%, one half value layer <strong>of</strong> shielding is required. From Appendix D,<br />
0.3 mm <strong>of</strong> lead will provide adequate shielding.<br />
<strong>The</strong> <strong>Design</strong> <strong>of</strong> <strong>Diagnostic</strong> <strong>Medical</strong> <strong>Facilities</strong> <strong>where</strong> Ionising Radiation is used 71