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The Design of Diagnostic Medical Facilities where ... - ResearchGate

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5.3.2 Nuclear medicine shielding calculation examples<br />

Example 5: Shielding required for gamma camera room<br />

A gamma camera room is adjacent to the reception area. 60 patients per week are scanned using a 99m Tc<br />

bone scanning agent with an administered activity <strong>of</strong> 600 MBq. Patients are scanned two hours post<br />

administration and scanning time per patient is 30 minutes. <strong>The</strong> distance from the patient to a person in the<br />

adjoining <strong>of</strong>fice is 3 m.<br />

What shielding is required for the wall between the camera room and the reception<br />

<strong>The</strong> dose from a single patient at the point <strong>of</strong> interest is given by equation 5.7:<br />

F<br />

D(t) = D(0)<br />

.<br />

× t × R<br />

t<br />

×<br />

d<br />

<strong>where</strong> Ḋ(0) is the product <strong>of</strong> the dose rate constant for the patient, having been administered 99m Tc and<br />

the activity administered (MBq), t is the scanning time, and F u<br />

and R t<br />

are the decay factor prior to<br />

scanning and the dose reduction factor during scanning respectively.<br />

u<br />

2<br />

For a workload <strong>of</strong> N w<br />

patients per week, the annual dose at a distance d from the patient is:<br />

.<br />

F<br />

D(t<br />

a)<br />

= N<br />

w<br />

× 52×<br />

D(0) × t × R<br />

t<br />

×<br />

d<br />

Values for the dose rate constant for the patient administered 99m Tc , R t<br />

and F u<br />

are given in Section 5.2.8<br />

as 0.0075 μSv m 2 /MBqh, 0.97 and 0.79.<br />

u<br />

2<br />

Thus:<br />

D(t a<br />

) = 60 x 52 x 0.0075 μSv m 2 /MBqh x 600 MBq x 0.5 h x 0.97 x<br />

= 598 μSv = 0.598 mSv<br />

0.79<br />

9<br />

For an occupancy factor <strong>of</strong> 1.0, and a dose constraint <strong>of</strong> 0.3 mSv, the transmission is<br />

0.3 mSv<br />

B =<br />

= 0.50<br />

0.598 mSv × 1<br />

To reduce the transmission to 50%, one half value layer <strong>of</strong> shielding is required. From Appendix D,<br />

0.3 mm <strong>of</strong> lead will provide adequate shielding.<br />

<strong>The</strong> <strong>Design</strong> <strong>of</strong> <strong>Diagnostic</strong> <strong>Medical</strong> <strong>Facilities</strong> <strong>where</strong> Ionising Radiation is used 71

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