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The Design of Diagnostic Medical Facilities where ... - ResearchGate

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Example 7: Shielding required for PET scanning room<br />

A PET facility scans 50 patients per week using 18 F FDG. <strong>The</strong> administered activity per scan is 555 MBq. <strong>The</strong><br />

uptake time is 1 hour and the average imaging time is 30 minutes.<br />

What shielding is required for the wall <strong>of</strong> the control room which is 3 m from the scanning table<br />

Because <strong>of</strong> the delay between administration and imaging, the activity in the patient will decrease by<br />

F = exp<br />

u<br />

- 0.693t<br />

T<br />

1 2<br />

u<br />

<strong>where</strong> t u<br />

is the uptake time(min) and T 1/2<br />

the half-life (min). For t u<br />

<strong>of</strong> 60 mins,<br />

-0.693×<br />

60<br />

F u<br />

= exp<br />

= 0.69<br />

110<br />

In most cases, the patient will void prior to imaging, thereby removing about 15% <strong>of</strong> the administered<br />

activity and decreasing the dose rate by a factor <strong>of</strong> 0.85. Because the 18 F FDG will decay during imaging,<br />

a further dose reduction factor R ti<br />

is applied<br />

D(t)<br />

= .<br />

D(0)<br />

R t i<br />

×<br />

t<br />

T<br />

= 1.443×<br />

t<br />

For a scanning time t <strong>of</strong> 30 mins, R ti<br />

is equal to 0.91.<br />

½<br />

× 1−<br />

exp<br />

− 0.693t<br />

T<br />

½<br />

Equation 5.8<br />

<strong>The</strong> dose D(t i<br />

) per imaging time at a distance 3 m from the patient is given by Equation 5.11<br />

D(t i<br />

) =<br />

2<br />

Fu<br />

0 .092 μSvm /MBqh × A<br />

o<br />

(MBq) × ti<br />

(h) × R<br />

ti<br />

× 0.85 ×<br />

2<br />

d (m)<br />

=<br />

0.69<br />

0 .092×<br />

555×<br />

0.5 × 0.91×<br />

0.85×<br />

9<br />

= 1.514 μSv<br />

2<br />

Scanning 50 patients per week, the annual dose at 3 m from the Table, D, is<br />

D(t a<br />

) = 1.514 μSv x 50 x 52 = 3936 μSv = 3.94 mSv<br />

If the shielding characteristics <strong>of</strong> the scanner are accurately known, then a dose reduction factor at<br />

some <strong>of</strong> the walls may be incorporated into the calculation (see Section 5.2.9). A more conservative<br />

approach ignores the potential dose reduction afforded by the scanner.<br />

It is assumed that only designated radiation workers will occupy the control room (dose constraint <strong>of</strong><br />

1 mSv) and that it has an occupancy factor <strong>of</strong> 1. <strong>The</strong> required transmission factor will be given by:<br />

B 1mSv<br />

=<br />

0.25<br />

3.936 mSv × 1<br />

=<br />

Using Table D.4 and Figures D.1 and D.2 from Appendix D, 10 mm lead or 13.3 cm concrete is required<br />

to provide the necessary shielding.<br />

<strong>The</strong> <strong>Design</strong> <strong>of</strong> <strong>Diagnostic</strong> <strong>Medical</strong> <strong>Facilities</strong> <strong>where</strong> Ionising Radiation is used 73

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