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Copyright 2004 by Marcel Dekker, Inc. All Rights Reserved.

Copyright 2004 by Marcel Dekker, Inc. All Rights Reserved.

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B. Recombination of the Dark Exciton in Magnetic FieldsOne can see from Eq. (37) that components of the magnetic field perpendicularto the hexagonal crystal axis mix the F = F2 dark-exciton states with therespective optically active F = F1 bright-exciton states. The dark-excitonstate with F = 0 is also activated due to its admixture with the F = F1 brightexcitonstates. In small NCs, for which the level splittings are on the order of10 meV, even the influence of strong magnetic fields can be considered as aperturbation. The case of large NCs for which g is of the same order as l B g e Hwill be considered later. The admixture in the F = 2 state is given <strong>by</strong>DC 2 ¼ l BHg pffiffipffiffi!eC 3 gh C þ2 e 2 e þ C þ 1 þ 3 gh C þ g e C þC1e 2 e 1 ; ð42Þ1where the constants C F are given in Eq. (21). The admixture in the F = 2exciton state of the F = 1 exciton state is described similarly.This admixture of the optically active bright-exciton states allows theoptical recombination of the dark exciton. The radiative recombination rateof an exciton state F can be obtained <strong>by</strong> summing Eq. (24) over all lightpolarizations [30]:1¼ 4e2 xn rs jFj 3m 2 0 c3 t jh0jpˆlj ˜C F ij 2 ;ð43Þwhere x and c are the light frequency and velocity, respectively, n r is therefractive index, and m 0 is the free-electron mass. Using Eqs. (26) and (28), weobtain the radiative decay time for the upper exciton state with F = 0,1¼8xn rP 2 Ks 0 9 137m 2 ð44Þ0 c2for the upper and lower exciton states with jFj = 1, correspondinglypp ffiffiffiffiffi !1s U;L1¼ 2 ffiffiffiffiffiffiffiffiffiffiffiffiffif 2 þ d b f Fpffiffiffiffiffiffiffiffiffiffiffiffiffi2 f 2 þ d3d1s 0ð45ÞUsing the admixture of the jFj = 1 states in the jFj = 2 exciton given <strong>by</strong> Eq.(42), we calculate the recombination rate of the jFj = 2 exciton in a magneticfield [3],1s 2 ðHÞ ¼ 3l2 B H2 sin 2 ðh H Þ 2g þ D 218D 2 2g h g e3g s 0ð46ÞThe characteristic time s 0 does not depend on the NC radius. For CdSe,calculations using 2P 2 /m 0 = 19.0 eV [31] give s 0 = 1.5 ns.<strong>Copyright</strong> <strong>2004</strong> <strong>by</strong> <strong>Marcel</strong> <strong>Dekker</strong>, <strong>Inc</strong>. <strong>All</strong> <strong>Rights</strong> <strong>Reserved</strong>.

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