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Quantitation of Tryptophan in <strong>Protein</strong>s 43<br />

3. The amount of tryptophan (w) is estimated from the relative absorbances at these<br />

wavelengths by the method of Goodwin and Morton (2) shown in Eq. 1.<br />

where<br />

x = total mole/L; w = tryptophan mole/L; (x – w) = tyrosine mole/L.<br />

e y = Molar extinction of tyrosine in 0.1 M alkali at 280 nm = 1576.<br />

e w = Molar extinction of tryptophan in 0.1 M alkali at 280 nm = 5225.<br />

Also, x is measured from E 294.4 (the molar extinction at this wavelength). This is<br />

2375 for both Tyr and Trp (since their absorption curves intersect at this wavelength).<br />

An accurate reading of absorbance at one other wavelength is then sufficient to<br />

determine the relative amounts of these amino acids.<br />

Therefore,<br />

E 280 = w ε w + (x – w)ε y<br />

w = (E 280 – x ε y )/( ε w - ε y)<br />

4. An alternative method of obtaining the ratios of Tyr and Trp is to use<br />

the formulae (Eq. 2) derived by Beaven and Holiday (5).<br />

M Tyr = (0.592 K 294 – 0.263 K 280) × 10 –3<br />

= (0.263 K 280 – 0.170 K 294) × 10 –3<br />

where M Tyr and M Trp are the moles of tyrosine and tryptophan in 1/ g of protein, and K 294 and<br />

K 280 are the extinction coefficients of the protein in 0.1 N alkali at 294 and 280 nm.<br />

Extinction values can be substituted for the K values to give the molar ratio of tyrosine<br />

to tryptophan according to the formula:<br />

4. Notes<br />

M Tyr / M Trp = (0.592 E 294 – 0.263 E 280)/( 0.263 E 280 – 0.170 E 294) (2)<br />

1. The extinction of nucleic acid in the 280 nm region may be as much as 10 times that of<br />

protein at the same wavelength and hence a few percent of nucleic acid can greatly<br />

influence the absorption.<br />

2. In this analysis, the tyrosine estimate may be high and that of tryptophan low. If amino<br />

acid analysis indicates absence of tyrosine, tryptophan is more accurately determined at<br />

its maximum, 280.5 nm.<br />

3. Absorption by most proteins in 0.1 M NaOH solution decreases at longer wavelengths<br />

into the region 330–450nm where tyrosine and tryptophan do not absorb. Suitable blanks<br />

for 294 and 280 nm are therefore obtained by measuring extinctions at 320 and 360 nm<br />

and extrapolating back to 294 and 280 nm.<br />

4. In proteins, in a peptide bond, the maximum of the free amino acids is shifted by 1–3 nm<br />

to a longer wavelength and pure peptides containing tyrosine and tryptophan residues are<br />

better standards than the free amino acids. A source of error may be due to turbidity in the<br />

solution and if a protein shows a tendency to denature, it is advisable to treat with a low<br />

amount of proteolytic enzyme to obtain a clear solution.<br />

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