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110 Mathematical Recreations

year just 365 days and making every fourth year a leap year

of 366 days. The Julian calendar spread abroad with other

important features of Roman culture, and was generally used

until 1582.

The Julian year was a little too long, and by 1582 the ac'

cumulated error amounted to 10 days. A second reform,

instituted by Pope Gregory XIII, compensated for the error

and required that for the future the last year of each century

should not be a leap year unless the number of the century

were divisible by 4. Thus, 1700, 1800, 1900, 2100,· .. are

not leap years, but 2000 is.

Gauss gave a formula for finding the day of the week corresponding

to a given date. This formula is:

W 55 D+ M + C+ Y (modulo 7),

where W is the day of the week (starting with Sunday = 1),

D is the day of the month, and M, C, and Yare numbers depending

on the month, the century and the year, respectively.

The values of M, C, and Yare given in the tables

on page 111.

In determining the value of Y, the number of the year

must be diminished by one if the month is January or

February.

Many tables and mechanisms have been devised to solve

this problem. We shall give two of the simplest, which are

nomograms.

The first is shown in Figure 17.

To find the day of the week corresponding to a given date,

on Figure 17, proceed as follows:

1. Write the given date as a set of four numbers - the

day of the month (called the Date in the first scale of the

nomogram), the month (third scale), the first two numbers

of the year (called the Century in the fourth scale), and the

last two numbers of the year (called the Year in the first

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