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Mathematical_Recreations-Kraitchik-2e

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Permutational Problems 221

Thus it takes 10 + 4(n - 4) + 11 = 4n + 5 trips to complete

the operation.

Tarry proposed a still further complication by adding to

the requirements made so far the assumption that one of the

husbands was a bigamist traveling with both his wives. The

problem can still be solved, but no fewer than 43 trips are

required for the transportation of 4 families.

4. THE THIEVES AND THE LOOT. Saint-Lague gave an

amusing problem of this sort:

Three robbers, old Babylas, his nephew Hilary, and Hilary's

son Sosthenes, stole a treasure chest from an old castle.

The treasure was hidden at the top of a tower overlooking a

river. To avoid pursuit they have had to destroy the ladders

by which they climbed up inside the tower, and their only

means of escape is to go down the outside of the tower by

means of a crude tackle they have with them. This consists

of a long rope with a basket at each end and a single pulley.

If the difference in weight of the contents of the two baskets

is greater than 20 pounds, the heavier basket descends too

rapidly for the safety of the robbers, though the box will

stand it. Babylas weighs 170 pounds, Hilary 100 pounds,

Sosthenes 80 pounds, and the treasure 60 pounds. But this

is not their only problem. When they reach the bottom they

divide the treasure into three unequal parts, the largest for

Babylas, and each puts his portion into a separate bag. They

must then cross the river in a boat so small that it will hold

only two men or one man and a bag. There is no honor

among them, and none of them wishes to leave his bag with

one of the others. However, they decide that the man who

is managing the boat will be too busy to tamper with the

bags. How did they make good their escape?

Solution: First they let the box down in one basket. When

that has reached the bottom Sosthenes climbs into the basket

at the top and goes down, bringing the treasure up. The box

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