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Permutational Problems 229

go back to their original positions. The first such operationyields

the permutations ACEBGDIFKHJA. The others

are found similarly.

If the number of children is even we may modify the problem

by requiring that every child have every other child but

one as his neighbor. Circular permutations satisfying this

requirement can be found from Figure 107 by marking an

extra point on the other diameter of the figure.

Here is a variation of the problem. n boys and n girls are

A

M

B

K

E

o

FIGURE 109.

H

FIGURE 110.

dancing in a circle, a boy between each two girls. Can one

make successive permutations in their order so that every

boy has every girl as neighbor just once?

In all there are n 2 pairs to be formed. In anyone round

there are 2n such pairs. If there are to be no repetitions or

OffilSSlOns, .. 2n n2 = 2" n arrangements must f orm t h e n d' d

2 eSlre

pairs, so n must be even, say n = 2p. Join the alternate vertices

of an inscribed regular n-gon, so as to form two inscribed

regular p-gons (as in Figure 109). Denote the boys by capital

letters and the girls by corresponding small letters. Letter

the points on the circle with the capital letters in order,

and letter the points of intersection of the two p-gons correspondingly,

as in the figure. The successive arrangements

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