VINNANDE VETANDE - Svenska Fysikersamfundet

) Den resulterande tryckkraften utgör i detta fall centripetalkraft
Fc = ∆p
⋅ A = ρ ⋅ g ⋅ h ⋅ A.
Olika delar av den horisontella vätskan har olika centripetalaccelerationer
2
eftersom a = x ⋅ω
c
Den resulterande kraften blir därför
2 2
l ⋅ω
⋅ ρ ⋅ A
l ⋅
Detta ger = ρ ⋅ g ⋅ h ⋅ A som ger h =
2
2g
Svar:
2 2
l ⋅ a
l ⋅ω
a) h = och b) h = .
g
2g
F
c
289
l
2 2
2
l ⋅ω
⋅ ρ ⋅ A
= ∫ x ⋅ω
⋅ ρ ⋅ A⋅
dx
=
.
2
0
2 2
ω