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Structural Health Monitoring Using Smart Sensors - ideals ...

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Samples<br />

3<br />

2<br />

1<br />

0<br />

-1<br />

-2<br />

Samples<br />

3<br />

2<br />

1<br />

0<br />

-1<br />

-2<br />

-3<br />

27.9 27.95<br />

Time (sec)<br />

28<br />

(a)<br />

Figure 5.25. Signals (a) before and (b) after resampling.<br />

-3<br />

27.9 27.95<br />

Time (sec)<br />

28<br />

(b)<br />

the filter is expressed in radian normalized to the sampling frequency of an upsampled<br />

signal. This filter is applied to the upsampled signal, which is three times longer than the<br />

original one, and then downsampled by a factor of 2. When a signal sampled at 101 Hz is<br />

resampled at 150 Hz, on the other hand, the rational factor, L<br />

M, is 150/101. Upsampling<br />

by a factor of 101 greatly increases the data size. A lowpass filter with a cutoff frequency<br />

of requires a large number of filter coefficients. If such a filter is applied to the<br />

upsampled signal, the upsampled signal is 101 times longer than the original one. Direct<br />

implementation of such resampling on resource-limited smart sensors is intractable.<br />

Polyphase implementation<br />

An FIR filter can be computationally much more inexpensive as a filter for<br />

resampling if the polyphase implementation is employed. The polyphase implementation<br />

leverages knowledge that upsampling involves inserting many zeroes and that an FIR<br />

filter does not need to calculate the output at all of the upsampled data points. This<br />

implementation of resampling is explained in this section mainly in the time domain<br />

because the extension of the method to achieve synchronized sensing is pursued using a<br />

time domain analysis. Oppenheim et al. (1999) provided a detailed description of the<br />

polyphase implementation in the Z-domain.<br />

Upsampling and lowpass filtering with an FIR filter can be written in the following<br />

manner:<br />

yn <br />

vl <br />

=<br />

N-1<br />

<br />

k=0<br />

xm<br />

,<br />

= <br />

,<br />

hk vn-k <br />

l = Lm, m =0, , , <br />

otherwise<br />

(5.16)<br />

85

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