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Chemical Thermodynamics of Tin - Volume 12 - OECD Nuclear ...

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A Discussion <strong>of</strong> selected references<br />

341<br />

[1973VAS/KOK]<br />

The heats <strong>of</strong> dissolution <strong>of</strong> metallic tin in hydrochloric acid solutions <strong>of</strong> hydrogen<br />

peroxide have been measured calorimetrically at 25 °C and ionic strengths 1, 2, 3, and<br />

4 M HCl. The enthalpies <strong>of</strong> formation <strong>of</strong> SnCl 4 in these solutions have been calculated.<br />

According to the authors a typical dissolution experiment can be represented<br />

by the following equation:<br />

β-Sn + 49.1 H 2 O 2 (sln 105.4H 2 O, 4.0HCl) + 197.0 HCl(sln 26.2 H 2 O, 0.25 H 2 O 2 ) <br />

SnCl 4 (sln 5175 H 2 O, 193 HCl, 47.1 H 2 O 2 ) + 47.1 H 2 O 2 (sln 110 H 2 O, 4.0 HCl,<br />

0.021 SnCl 4 ) + 193 HCl(sln 26.8 H 2 O, 0.24 H 2 O 2 , 0.005 SnCl 4 ) + 4 H 2 O(sln <strong>12</strong>94 H 2 O,<br />

48.2 HCl, 11.8 H 2 O 2 , 0.25 SnCl 4 ). (A.52)<br />

The slight stoichiometric inconsistencies in Eq. (A.52) above are<br />

inconsequential and due to rounding errors.<br />

ο<br />

m<br />

Δ fH<br />

(H 2 O 2 , sln 105.4 H 2 O, 4.0 HCl) = Δ fHm<br />

(H 2 O 2 , sln 110 H 2 O, 4.0H Cl,<br />

ο<br />

0.021 SnCl 4 ) = Δ H (H 2 O 2 , sln ∞ H 2 O),<br />

ο<br />

m<br />

Δ fH<br />

(HCl, sln 26.2 H 2 O, 0.25 H 2 O 2 ) = Δ fHm(HCl, sln 26.8 H 2 O, 0.24 H 2 O 2 ,<br />

ο<br />

0.005 SnCl 4 ) = Δ H (HCl, sln 26.2 H 2 O)<br />

f<br />

ο<br />

m<br />

Δ H (H 2 O, 0.037 HCl, 0.009 H 2 O 2 , 0.0002 SnCl 4 ) = Δ H<br />

ο<br />

ο<br />

f<br />

f<br />

f<br />

ο<br />

m<br />

m<br />

m<br />

(H 2 O, l).<br />

Consequently Eq. (A.52) can be simplified to Eq. (A.53)<br />

β-Sn + 2 H 2 O 2 (sln ∞ H 2 O) + 4 HCl(sln 26.2 H 2 O) SnCl 4 (sln) + 4 H 2 O(l).<br />

(A.53)<br />

Thus the enthalpy <strong>of</strong> formation <strong>of</strong> SnCl 4 in these solutions can essentially be<br />

obtained by Eq. (A.54):<br />

ο<br />

m<br />

ο<br />

ο<br />

Δ fH<br />

(SnCl 4 , sln) = Δ rHm(A.52) − 4Δ fHm(H 2 O, l) + 2Δ fHm(H 2 O 2 , sln ∞ H 2 O)<br />

ο<br />

+ 4Δ H (HCl, sln 26.2 H 2 O). (A.54)<br />

f<br />

m<br />

ο<br />

m<br />

Using the value for Δ fH<br />

(H 2 O, l) given by CODATA [1989COX/WAG] and<br />

ο<br />

ο<br />

the values for Δ fHm<br />

(H 2 O 2 , sln ∞ H 2 O) and Δ fHm<br />

(HCl, sln 26.2 H 2 O) given by<br />

[1982WAG/EVA] essentially the same results were obtained as those listed by the<br />

authors (Table A-28).<br />

The results <strong>of</strong> this work are the basis for the determination <strong>of</strong> standard<br />

enthalpies <strong>of</strong> formation <strong>of</strong> tin compounds, and are accepted by the Review Team for<br />

recalculations.<br />

ο<br />

CHEMICAL THERMODYNAMICS OF TIN, ISBN 978-92-64-99206-1, © <strong>OECD</strong> 20<strong>12</strong>

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