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Chemical Thermodynamics of Tin - Volume 12 - OECD Nuclear ...

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476<br />

B Ionic strength corrections<br />

Table B-5: (continued)<br />

j k ε(j,k) Comments<br />

3<br />

Hedta − Li + —<br />

Na + – 0.10 ± 0.14<br />

K + 0.31 ± 0.18<br />

3<br />

PO − 4<br />

Li + —<br />

Na + − 0.25 ± 0.03†<br />

Evaluated in Section VIII.3.7 <strong>of</strong> [2005HUM/AND].<br />

K + − 0.09 ± 0.02 Reported by Ciavatta [1980CIA].<br />

3<br />

Si3O 6(OH) − 3 Li + —<br />

Na + − 0.25 ± 0.03 Estimated in [1992GRE/FUG].<br />

K + —<br />

3<br />

Si3O 5(OH) − 5 Li + —<br />

Na + − 0.25 ± 0.03 Estimated in [1992GRE/FUG].<br />

K + —<br />

3<br />

Si4O 7(OH) − 5 Li + —<br />

Na + − 0.25 ± 0.03 Estimated in [1992GRE/FUG].<br />

K + —<br />

3<br />

Ni(CN) − 5<br />

Li + —<br />

Na + 0.25 ± 0.14 Evaluated in [2005GAM/BUG] (see Section V.7.1.2.1.1).<br />

K + —<br />

3<br />

Am(CO 3) 3<br />

Li + —<br />

Na + − 0.23 ± 0.07 Evaluated Section <strong>12</strong>.6.1.1.1 [2003GUI/FAN], from Δε n in<br />

3+ 2−<br />

NaCl solution for the reactions An + n CO 3<br />

<br />

(3−2 n)<br />

An(CO )<br />

3+ −<br />

(An = Am, Cm) based on ε (Am ,Cl ) =<br />

K + —<br />

3<br />

n<br />

+ 2−<br />

3<br />

(0.23 ± 0.02) kg·mol −1 and ε (Na ,CO ) = – (0.08 ± 0.03)<br />

kg·mol −1 .<br />

3<br />

Am(ox) − 3<br />

Li + —<br />

Na + − 0.23 ± 0.10 Estimated in [2005HUM/AND], Section VI.13.2.1 by assuming<br />

ε(Na ,Am(ox) 3 ) ≈ ε(Na ,Am(CO 3 ) 3 ) .<br />

+ 3− + 3−<br />

K + —<br />

3<br />

Np(CO 3) 3<br />

Li + —<br />

Na + —<br />

K + − 0.15 ± 0.07 Estimated by analogy in [2001LEM/FUG] (Section<br />

<strong>12</strong>.1.2.1.5).<br />

3<br />

NpO 2(CO 3) 2 Li + —<br />

Na + − 0.33 ± 0.17 Calculated in [2001LEM/FUG] (Section <strong>12</strong>.1.2.1.3).<br />

K + —<br />

(Continued on next page)<br />

CHEMICAL THERMODYNAMICS OF TIN, ISBN 978-92-64-99206-1, © <strong>OECD</strong> 20<strong>12</strong>

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