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Travaux sur les symétries de Lie des équations aux ... - DMA - Ens

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204just by virtue of the reality i<strong>de</strong>ntities (7.28). It also follows rather triviallythat the dual differential equation:w zz (z) = Θ zz(z, ζ(z, w(z), wz (z)), ξ(z, w(z), w z (z)) )= Φ ( z, w(z), w z (z) )is also just the conjugate differential equation.To the differential equation y xx = F and to its dual b aa = F ∗ are associatedtwo submanifolds of solutions:M = M (E ) := {( x, y, a, b ) ∈ K × K × K × K: y = Q(x, a, b) } ,together with:M ∗ = M (E ∗ ) := {( a, b, x, y ) ∈ K × K × K × K: b = Q ∗ (a, x, y) } ,and as one obviously guesses, the duality, when viewed within submanifoldsof solutions, just amounts to permute variab<strong>les</strong> and parameters:M ∋ (x, y, a, b) ←→ (a, b, x, y) ∈ M ∗ .In the CR case, if we <strong>de</strong>note by ˜z and ˜w two in<strong>de</strong>pen<strong>de</strong>nt complex variab<strong>les</strong>which correspond to the complexifications of z and w (respectively ofcourse), the duality takes place between the so-called extrinsic complexification([13, 14, Me2005a, Me2005b, 18, 19]):M = M c := {( z, w, ˜z, ˜w ) ∈ C × C × C × C: w = Θ ( z, ˜z, ˜w )}of M in one hand, and in the other hand, its own transformation 21 :M ∗ = ∗ c (M c ) := {(˜z, ˜w, z, w ) ∈ C × C × C × C: ˜w = Θ (˜z, z, w )}un<strong>de</strong>r the involution:∗ c( z, w, ˜z, ˜w ) := (˜z, ˜w, z, w )which clearly is the complexification of the natural antiholomorphic involution:∗ ( z, w, z, w ) := ( z, w, z, w )that fixes M pointwise, as it fixes any other real analytic subset of C 2 . Here,one has M ∗ = ∗(M ) — which is ≠ M in general — and of course also(M∗ )∗ = M .So in terms of the coordinates (x, a, b) on M and of the coordinates(a, x, y) on M ∗ , the duality is the map:(x, a, b) ↦−→ ( a, x, Q(x, a, b) )with inverse:(a, x, y) ↦−→ ( x, a, Q ∗ (a, x, y) ) .21 Be careful not to write {( z, w, ˜z, ˜w ) : ˜w = Θ (˜z, z, w )} , because this would regivethe same subset M of C 2 × C 2 , due to the reality i<strong>de</strong>ntities (7.28).

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