326the fourth lines of (3.18), we may permute freely certain indices in some ofthe terms insi<strong>de</strong> the brackets. This yields the passage from lines 2, 3 and 4of (3.18) to lines 2, 3 and 4 of (3.20).It remains to explain how we pass from the fifth (last) line of (3.18) to thefifth (last) line of (3.20). The bracket in the fifth line of (3.18) contains threeterms: [−T 1 − T 2 − T 3 ]. The term T 3 involves the product δ k 1,k 3i 2 , i 1, which werewrite as δ k 3,k 1i 1 , i 2, in or<strong>de</strong>r that i 1 appears before i 2 . Then, we rewrite the threeterms in the new or<strong>de</strong>r [−T 2 − T 3 − T 1 ], which yields:(3.22)∑ [−δ k 1,k 3i 1 , i 2X k 2y − δ k 3,k 1i 1 , i 2X k 2y − δ k 2,k 3i 1 , i 2X k 1yk 1 ,k 2 ,k 3]y k1 y k2 ,k 3.It remains to observe that we can permute k 2 and k 3 in the first term −T 2 ,which yields the last line of (3.20). The <strong>de</strong>tailed proof is complete.3.23. Final perfect expression of Y i1 ,i 2 ,i 3. Thanks to similar (longer) computations,we have obtained an expression of Y i1 ,i 2 ,i 3which we consi<strong>de</strong>r tobe in final harmonious shape. Without copying the intermediate steps, let uswrite down the result. The comments which are necessary to read it and tointerpret it start just below.Y i1 ,i 2 ,i 3= Y x i 1x i 2x i 3 + ∑ k 1[δ k 1i 1Y x i 2x i 3y + δ k 1i 2Y x i 1x i 3y + δ k 1i 3Y x i 1x i 2y − X k 1x i 1x i 2x i 3]y k1 +(3.24)+ ∑ k 1 ,k 2[δ k 1,k 2i 1 , i 2Y x i 3y 2 + δ k 1,k 2i 3 , i 1Y x i 2y 2 + δ k 1,k 2i 2 , i 3Y x i 1y 2−]−δ k 1i 1X k 2x i 2x i 3y − δk 1i 2X k 2x i 1x i 3y − δk 1i 3X k 2yx i 1x i 2y k1 y k2 ++ ∑ []δ k 1,k 2 ,k 3i 1 , i 2 , i 3Y y 3 − δ k 1,k 2i 1 , i 2X k 3− δ k 1,k 2x i 3y 2 i 1 , i 3X k 3− δ k 1,k 2x i 2y 2 i 2 , i 3X k 3yx i 1y 2 k1 y k2 y k3 +k 1 ,k 2 ,k 3+ ∑ [−δ k 1,k 2 ,k 3i 1 , i 2 , i 3X k 4]yy 3 k1 y k2 y k3 y k4 +k 1 ,k 2 ,k 3 ,k 4+ ∑ k 1 ,k 2[δ k 1,k 2i 1 , i 2Y x i 3y + δ k 1,k 2i 3 , i 1Y x i 2y + δ k 1,k 2i 2 , i 3Y x i 1y −]−δ k 1i 1X k 2x i 2x − i 3 δk 1i 2X k 2x i 1x − i 3 δk 1i 3X k 2yx i 1x i 2 k1 ,k 2++ ∑ [δ k 1,k 2 ,k 3i 1 , i 2 , i 3Y y 2 + δ k 3,k 1 ,k 2i 1 , i 2 , i 3Y y 2 + δ k 2,k 3 ,k 1i 1 , i 2 , i 3Y y 2−k 1 ,k 2 ,k 3−δ k 1,k 2i 1 , i 2X k 3x i 3y − δk 3,k 1i 1 , i 2X k 2x i 3y − δk 2,k 3i 1 , i 2X k 1x i 3y −−δ k 1,k 2i 1 , i 3X k 3x i 2y − δk 3,k 1i 1 , i 3X k 2x i 2y − δk 2,k 3i 1 , i 3X k 1x i 2y −−δ k 1,k 2i 2 , i 3X k 3x i 1y − δk 3,k 1i 2 , i 3X k 2x i 1y − δk 2,k 3i 2 , i 3X k 1x i 1y]y k1 y k2 ,k 3+
+ ∑k 1 ,k 2 ,k 3 ,k 4[−δ k 1,k 2 ,k 3i 1 , i 2 , i 3X k 4y 2 − δ k 2,k 3 ,k 1i 1 , i 2 , i 3X k 4y 2 − δ k 3,k 2 ,k 1i 1 , i 2 , i 3X k 4y 2 −−δ k 3,k 4 ,k 1i 1 , i 2 , i 3X k 2y 2 − δ k 3,k 1 ,k 4i 1 , i 2 , i 3X k 2y 2 − δ k 1,k 3 ,k 4i 1 , i 2 , i 3X k 2+ ∑ [−δ k 1,k 2 ,k 3i 1 , i 2 , i 3X k 4y − δ k 2,k 3 ,k 1i 1 , i 2 , i 3X k 4y − δ k 3,k 1 ,k 2i 1 , i 2 , i 3X k 4yk 1 ,k 2 ,k 3 ,k 4+ ∑k 1 ,k 2 ,k 3[δ k 1,k 2 ,k 3i 1 , i 2 , i 3Y y − δ k 1,k 2i 1 , i 2X k 3x i 3 − δk 1,k 2i 1 , i 3X k 3x i 2 − δk 1,k 2i 2 , i 3X k 3x i 1327]yy 2 k1 y k2 y k3 ,k 4+]y k1 ,k 2y k3 ,k 4+]y k1 ,k 2 ,k 3++ ∑ [−δ k 1,k 2 ,k 3i 1 , i 2 , i 3X k 4y − δ k 4,k 1 ,k 2i 1 , i 2 , i 3X k 3y − δ k 3,k 4 ,k 1i 1 , i 2 , i 3X k 2y − δ k 2,k 3 ,k 4i 1 , i 2 , i 3X k 1yk 1 ,k 2 ,k 3 ,k 43.25. Comments, analysis and induction. First of all, by comparing thisexpression of Y i1 ,i 2 ,i 3with the expression (2.8) of Y 3 , we easily guess a partof the (inductional) dictionary beween the cases n = 1 and the case n 1.For instance, the three monomials [·](y 1 ) 3 , [·] y 1 y 2 and [·] (y 1 ) 2 y 2 in Y 3 arereplaced in Y i1 ,i 2 ,i 3by the following three sums:(3.26) ∑∑∑[·]y k1 y k2 y k3 , [·] y k1 y k2 ,k 3, and [·]y k1 y k2 y k3 ,k 4.k 1 ,k 2 ,k 3 k 1 ,k 2 ,k 3 k 1 ,k 2 ,k 3 ,k 4Similar formal correspon<strong>de</strong>nces may be observed for all the monomials ofY 1 , Y i1 , of Y 2 , Y i1 ,i 2and of Y 3 , Y i1 ,i 2 ,i 3. Generally and inductively speaking,the monomial(3.27) [·](y λ1 ) µ1 · · ·(y λd ) µ dappearing in the expression (2.25) of Y κ should be replaced by a certainmultiple sum generalizing (3.26). However, it is necessary to think, to pauseand to search for an appropriate formalism before writing down the <strong>de</strong>siredmultiple sum.The jet variable y λ1 should be replaced by a jet variable corresponding toa λ 1 -th partial <strong>de</strong>rivative, say y k1 ,...,k λ1, where k 1 , . . ., k λ1 = 1, . . .,n. Forthe moment, to simplify the discussion, we leave out the presence of a sumof the form ∑ k 1 ,...,k λ1. The µ 1 -th power (y λ1 ) µ 1should be replaced not by(y k1 ,...,k λ1) µ1,but by a product of µ1 different jet variab<strong>les</strong> y k1 ,...,k λ1of lengthλ, with all indices k α = 1, . . .,n being distinct. This rule may be confirmedby inspecting the expressions of Y i1 , of Y i1 ,i 2and of Y i1 ,i 2 ,i 3. So y k1 ,...,k λ1should be <strong>de</strong>veloped as a product of the form(3.28) y k1 ,...,k λ1y kλ1 +1,...,k 2λ1 · · · y k(µ1 −1)λ 1 +1,...,k µ1 λ 1,where(3.29) k 1 , . . .,k λ1 , . . .,k µ1 λ 1= 1, . . ., n.]y k1 y k2 ,k 3 ,k 4.
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Joël M E R K E RÉcole Normale Sup
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§1. INTRODUCTIONSeveral physically
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e a collection of m analytic second
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7where the indices j, l 1 vary in {
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This phenomenon could be explained
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This yields the prolongation of the
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X(x, y) and Y (x, y) such that it m
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2.23. Compatibility conditions for
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This lemma is left to the reader; a
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simplification nor any reordering:(
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aleza, y por otra, las organizacion
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computational level (differential-g
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For instance, in the case m = 2, by
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in (3.11). The second equation that
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Similarly, the second equation take
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order derivatives of X and of the Y
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Lemma 3.32. The system yxx j = F j
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Lemma 3.45. The following quadratic
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often be denoted by the sign “·
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1Now, taking account of the factor
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conditions, totally equivalent to t
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43remaining terms afterwards:(3.71)
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Here, the sign ≡ precisely means:
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Next, replacing plainly (3.64) in (
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49the order of §3.73. We get:(3.89
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51Multiplying by −2 and reorganiz
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⎧Θ l 1y l 2 = −Ll 1l 1 ,l 1 ,y
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+ 1 ∑4 δj l 1Hl k 2L k k,kk− 2
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+ 1 ∑2 δj l 1Hl k 3M l2 ,kk+ 1 4
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In the hardest techical part of thi
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− 1 3+ 1 3− 1 4+ 1 4∑Hl k 1H
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− 1 3∑kL l 1l1 ,k,x Hk l 1+ 1 3
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Here, the sign ≡ means “modulo
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Thirdly, put j := l 2 in (3.108) wi
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69correct. We get:(4.29)0 =?== −
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Next, apply the operator ∑ k Ll 2
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73Writing term by term the substrac
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of the terms of the subgoal (4.29):
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77+ 1 2∑kH k l 1 ,y l 2 Hl 2k15
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79= − X xx Yx j + Y jm∑+++++l 1
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Our first task is to compute the de
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Replacing this expression of A k in
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85have the continuation(5.17) −y
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87and where thirdly (we are nearly
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89obtain:(5.23)III :=m∑m∑l 1 =1
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[GTW1989] GRISSOM, C.; THOMPSON, G.
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93Nonalgebraizable real analytic tu
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and of CR dimension m = n − d ≥
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coordinates z ′ = 2i ln(z/z p ),
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{x ∈ K n : |x| < ρ} for some ρ
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(2) A K-algebraic inversion mapping
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(1) The complex Lie algebra Hol(M,
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Proposition 3.1. Let t ↦→ G i (
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The first relation gives nothing, s
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with |β∗ k | ≥ 1 and integers
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Clearly, the left hand side is an a
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field X 1 ′ := h ∗ (X 1 ). Taki
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which yields after differentiating
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117Im w∆ n(ρ 4 )∆ n(ρ 1 )∆
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[∂ i,ei H ei (t ′ )] t ′ =He
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p = (w p , z p , ζ p , ξ p ) ∈
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Finite nondegeneracy is interesting
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such that |ω j i ∗ ,β∗ i(t,
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for k even, we have Γ k (z (k) ) =
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that for every local holomorphic se
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h(t) = ˜H(t, J l 0µ 0¯h(0)) with
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infinite families of pairwise non b
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functions w(z)). The coefficients R
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Then the Lie criterion states that
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y k ′ = λk k y k and w ′ = µ
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The last statements of Corollaries
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[Sha2000] SHAFIKOV, R.: Analytic co
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Here x = (x 1 , . . ., x n ) ∈ K
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Consequently, for the case κ = 2,
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are devoted to provide a general on
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for l = 1, . . .,m such that the lo
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Lemma 8.1. The following conditions
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155namely X ←→ X + X ←→ X .
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In terms of Sussmann’s approach [
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x κ−1 χ κ−1 + O(|x| κ ) + O
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Observe that these expressions are
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where the first term I involves onl
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I 5 = ∑ i 1I 6 = ∑ i 1 ,i 2I 7
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U 2 U κ−1 , we obtain the five f
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and U 2 U κ−1 , we obtain the fi
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following equations for j = 1, . .
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linear equations:(7.28) ⎧0 = Rx j
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175R j containing at least one part
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177[3] :∑σ∈S κ−1κδ l,....
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the values of the partial derivativ
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also appears some derivatives Q l
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[5] F. ENGEL; LIE, S.: Theorie der
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185Nonrigid sphericalreal analytic
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origin:{ ( ∣ ∣ )AJ 4 1∣∣∣
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I 2 characterizes equivalence to w
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y means of a fundamental, elementar
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2) When M is Levi nondegenerate at
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195holding in C { z ′ , z ′ , w
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Fortunately for our present purpose
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We notice passim that S ≡ Q x (no
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for a certain local K-analytic new
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Conversely, if y xx (x) = F ( x, y(
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205But we may also express the dual
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Then thanks to a straightforward ap
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and we then expand carefully the re
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explicit computation, so let us rew
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213+T ah3Q 2 a Q b∆(aa|b)∆(b|bb
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215Vanishing Hachtroudi curvaturean
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to fix the ideas, it will be assume
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then by replacing the(so obtained)v
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and also in addition the fact that
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and this defines without ambiguity
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the leaves of this local foliation
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Then by differentiating with respec
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∂Here, the coefficients of the2 T
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231for (7.28):( )∂□ ·∂a □
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233Lie symmetriesof partial differe
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Differentiating the first equation
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Example 1.21. (Continued) With n =
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defined by the graphed equations:((
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for some two local analytic maps Π
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Proof. Let l = l ( x i , y j , yβ(
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complementary views on the same obj
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Classification problem 3.11. Classi
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Definition 4.10. L is an infinitesi
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Convention 5.2. The letters R will
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Assuming that dimSYM(E 1 ) = 8, tak
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Restarting from §4.1, let ϕ a Lie
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Here, R j l 1 ,kare universal polyn
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Lemma 6.34. Let M be a submanifold
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where the expressions D β,β1 are
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Then the sum L + L is tangent to M
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Lemma 7.11. ([CM1974, BER1999, Me20
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where(7.33) ∆ := ∑1kn∂ 2∂x
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with r, s being unspecified functio
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and moreover, all other, higher ord
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To conclude, we replace X xx so obt
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- Page 285 and 286: espect to x 1 and (8.96) 2 with res
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- Page 291 and 292: 291are obtained by equating to zero
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- Page 297 and 298: 11.4. Regularity and jet parametriz
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- Page 305 and 306: 305II: Explicit prolongations of in
- Page 307 and 308: Define then the transformed jet ϕ
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- Page 311 and 312: 311[Ol1986], [BK1989]):(Y(1.31)⎧
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- Page 325: Next, we gather the underlined term
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- Page 337 and 338: 337Theorem 3.73. For every κ 1 an
- Page 339 and 340: Theorem 3.79. For every integer κ
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- Page 343 and 344: 343form:(4.12)κ+1Yκ j = Y jx κ +
- Page 345 and 346: eing related to the number 2 in the
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- Page 349 and 350: Secondly:(5.3)Y j i 1 ,i 2= Y jx i
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- Page 355 and 356: with respect to the variables x i 1
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- Page 361 and 362: Open problem 1.17. For n = 2 establ
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- Page 365 and 366: eplacing the third column by the se
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- Page 369 and 370: e written under the specific form:(
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- Page 373 and 374: 3.12. Principal unknowns. As there
- Page 375 and 376: 375Sixthly:(3.22) ⎧δ k 1j 1Θ n+
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are a consequence of (I’), (I”)
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379IV: BibliographyREFERENCES[Ar198
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[G1989] GARDNER, R.B.: The method o
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[Me2005a] MERKER, J.: On the local