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Travaux sur les symétries de Lie des équations aux ... - DMA - Ens

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Here, the sign ≡ means “modulo zero or<strong>de</strong>r terms”. Before proceding further,recall the correspon<strong>de</strong>nce between partial differential relations:(4.13)(I) = (3.106),(II) = (3.108),(III) = (3.110),(IV) = (3.96).However, these coup<strong>les</strong> of equivalent i<strong>de</strong>ntities are written slightly differently,as may be read by comparison. To fix i<strong>de</strong>as and to facilitate the eyecheckingof our subsequent computations, we shall only use and refer to theexact writing of (3.106), of (3.108), of (3.110) and of (3.96).4.14. Construction of a gui<strong>de</strong>. So we want to show that the approximate relation(4.8) is a consequence, by differentiations and by linear combinations,of the approximate i<strong>de</strong>ntities (4.12). The interest of working with approximatei<strong>de</strong>ntities is that formal computations are lightened substantially. Afterhaving discovered which linear combinations and which differentiations areappropriate, i.e. after having constructed a “gui<strong>de</strong>”, in §4.22 below, we shallwrite down the complete computations, including all zero or<strong>de</strong>r terms, followingour gui<strong>de</strong>.We shall use two indices l 1 and l 2 with 1 l 1 , l 2 m and, crucially,l 2 ≠ l 1 . Again, the assumption m 2 is used strongly.Firstly, put j := l 1 in (3.106) mod with l 2 ≠ l 1 and differentiate withrespect to y l 1:(4.15) 0 ≡ −2G l 1y l 1y l 1 + 2Gl 2y l 2y l 1 + Hl 1l 1 ,xy l 1 − Hl 2l 2 ,xy l 1 .Secondly, put j := l 2 in (3.106) mod with l 1 ≠ l 2 and differentiate withrespect to y l 2:(4.16) 0 ≡ −2G l 2y l 1y l 2 + Hl 2l 1 ,xy l 2 .Thirdly, put j := l 2 in (3.108) mod with l 1 ≠ l 2 and differentiate with respectto x:(4.17) 0 ≡ − 1 2 Hl 2l 1 ,y l 2x + 1 3 Hl 1l 1 ,y l 1x + Ll 2l1 ,l 2 ,xx − 2 3 Ll 1l1 ,l 1 ,xx .Fourthly, put j := l 1 in (3.108) mod with l 2 ≠ l 1 and differentiate with respectto x:(4.18) 0 ≡ − 1 2 Hl 1l 1 ,y l 2x + 1 6 Hl 2l 2 ,y l 2x + Ll 1l1 ,l 2 ,xx − 1 3 Ll 2l2 ,l 2 ,xx .Fithly, permute the indices (l 1 , l 2 ) ↦→ (l 2 , l 1 ):(4.19) 0 ≡ − 1 2 Hl 2l 2 ,y l 1x + 1 6 Hl 1l 1 ,y l 1x + Ll 2l2 ,l 1 ,xx − 1 3 Ll 1l1 ,l 1 ,xx .65

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