11.07.2015 Views

Travaux sur les symétries de Lie des équations aux ... - DMA - Ens

Travaux sur les symétries de Lie des équations aux ... - DMA - Ens

Travaux sur les symétries de Lie des équations aux ... - DMA - Ens

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

364for j 1 , j 2 = 1, . . ., n. The expression of Y j1 does not matter for us here.Specifying this formula to the the case n = 2 and taking account of thesymmetry Y 1,2 = Y 2,1 we get the following three second or<strong>de</strong>r coefficients:(2.15) ⎧Y 1,1 = Y x 1 x 1 + y x 1 · {2 }Y x 1 y − X 1x 1 x + 1 yx 2 · {−X } 2x 1 x + 1+ y x 1 y x 1 · {Y }yy − 2 X 1x 1 y + yx 1 y x 2 · {−2X 2x y}+ 1+ y x 1 y x 1 y x 1 · {−X }yy1 + yx 1 y x 1 y x 2 · {−Xyy} 2 ,Y 1,2 = Y x 1 x 2 + y x 1 · {Y }x 2 y − X 1x⎪⎨1 x + 2 yx 2 · {Y }x 1 y − X 2x 1 x + 2+ y x 1 y x 1 · {−X } 1x 2 y + yx 1 y x 2 · {Yyy − X 1x 1 y − X 2x y}+ 2+ y x 2 y x 2 · {−X 2x y}+ 1+ y x 1 y x 1 y x 2 · {−X 1yy}+ yx 1 y x 2 y x 2 · {−X 2yy},Y 2,2 = Y x 2 x 2 + y x 1 · {−X }x 1 2 x + 2 yx 2 · {2 }Y x 2 y − Xx 2 2 x + 2+ y x 1 y x 2 · {−2 }X 1x⎪⎩2 y + yx 2 y x 2 · {Yyy − 2 X 2x y}+ 2+ y x 1 y x 2 y x 2 · {−X }yy1 + yx 2 y x 2 y x 2 · {−Xyy} 2 .We would like to mention that the computation of Y j1 ,j 2, 1 j 1 , j 2 2,above is easier than the verification of (2.10). Based on the three formulas(2.15), we claim that we can guess the second and the third equations,which would be obtained by <strong>de</strong>veloping and by simplifying (2.9), namelywith y x 1 x 2 and with y x 2 x 2 instead of y x 1 x2 in (2.10). Our dictionary to translatefrom the first formula (2.15) to (2.10) may be <strong>de</strong>scribed as follows.Begin with the Jacobian <strong>de</strong>terminant(2.16)∣∣X 1 xX 1 1 xX 1 2 y ∣∣∣∣∣X 2 xX 2 1 xX 2 2 yY x 1 Y x 2 Y yof the change of coordinates (2.2). Since this change of coordinates is closeto the i<strong>de</strong>ntity, we may consi<strong>de</strong>r that the following Jacobian matrix approximationholds:⎛⎞ ⎛(2.17) ⎝ X1 xX 1 1 xX 1 2 yX 2 xX 2 1 xX 2 ⎠ ∼ 2 y = ⎝ 1 0 0⎞0 1 0 ⎠ .Y x 1 Y x 2 Y y 0 0 1The jacobian matrix has three columns. There are six possible second or<strong>de</strong>r<strong>de</strong>rivatives with respect to the variab<strong>les</strong> (x 1 , x 2 , y), namely(2.18) (·) x 1 x 1, (·) x 1 x 2, (·) x 2 x 2, (·) x 1 y, (·) x 2 y, (·) yy .In the Jacobian <strong>de</strong>terminant (2.16), by replacing any one of the threecolumns of first or<strong>de</strong>r <strong>de</strong>rivatives with a column of second or<strong>de</strong>r <strong>de</strong>rivatives,we obtain exactly 3 × 6 = 18 possible <strong>de</strong>terminants. For instance, by

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!