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Travaux sur les symétries de Lie des équations aux ... - DMA - Ens

Travaux sur les symétries de Lie des équations aux ... - DMA - Ens

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322tiny <strong>de</strong>tail. Without such a care, it would be impossible to claim that some ofour subsequent computations, for which we will not provi<strong>de</strong> the intermediatesteps, may be redone and verified. Consequently, we will expose our ru<strong>les</strong>of formal computation thoroughly.Replacing the value of Y 1 just obtained in the induction formula (3.4) 2and <strong>de</strong>veloping, we may conduct the very first steps of the computation:Y i1 ,i 2= Di 2 2(Y i1 ) − ∑ )Di 1 2(X k 1y i1 ,k 1k 1=⎛⎝ ∂∂x i 2 + y i 2∂∂y + ∑ k 1y i2 ,k 1∂⎞ ⎛⎠∂y k1⎝Y x i 1 + ∑ k 1[δ k 1i 1Y y − X k 1x i 1]y k1 +⎞+ ∑ ] [−δ k 1i 1X k 2y y k1 y k2⎠ − ∑ ][X k 1x + y i 2 i 2X k 1y y i1 ,k 1k 1 ,k 2 k 1(3.10)( ∂=∂x i 2) ⎛ ⎞⎝Y x i 1 + ∑ [δ k 1i 1Y y − X k 1]yx i 1 k1 + ∑ [ ]−δ k 1i 1X k 2y y k1 y k2⎠ +k 1 k 1 ,k 2( ) ⎛ ⎞∂+ y i2⎝Y∂y x i 1 + ∑ [δ k 1i 1Y y − X k 1]yx i 1 k1 + ∑ [ ]−δ k 1i 1X k 2y y k1 y k2⎠+k 1 k 1 ,k 2⎛ ⎞ ⎛+ ⎝ ∑ ∂y i2 ,k 1⎠∂y k1k 1+ ∑ k 1[−X k 1x i 2⎝Y x i 1 + ∑ k 1[δ k 1i 1Y y − X k 1x i 1]y k1 ,i 1+ ∑ k 1[−X k 1y]y i2 y i1 ,k 1⎞]y k1 + ∑ [ ]−δ k 1i 1X k 2y y k1 y k2⎠ +k 1 ,k 2= Y x i 1x i 2 + ∑ [δ k 1i 1Y x i 2y − X k 1]yx i 1x i 2 k1 + ∑ [ ]−δ k 1i 1X k 2yx i 2y k1 y k2 +k 1 k 1 ,k 2+ Y x i 1y y i2 + ∑ [δ k 1i 1Y yy − X k 1]yx i 1y k1 y i2 + ∑ [ ]−δ k 1i 1X k 2yy y k1 y k2 y i2 +k 1 k 1 ,k 2+ ∑ [δ k 1i 1Y y − X k 1]yx i 1 i2 ,k 1+ ∑ [−δ k 1i 1X k 2y]y k2 y i2 ,k 1+ ∑ [ ]−δ k 1i 1X k 2y y k1 y i2 ,k 2+k 1 k 1 ,k 2 k 1 ,k 2+ ∑ [−X k 1]yx i 2 k1 ,i 1+ ∑ [k 1 k 1−X k 1y]y i2 y i1 ,k 1.Some explanations are nee<strong>de</strong>d about the computation of the last two termsof line 11, i.e. about the passage from line 7 of (3.10) just above to line 11.

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