11.07.2015 Views

Principles of Modern Radar - Volume 2 1891121537

Principles of Modern Radar - Volume 2 1891121537

Principles of Modern Radar - Volume 2 1891121537

SHOW MORE
SHOW LESS
  • No tags were found...

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

44 CHAPTER 2 Advanced Pulse Compression Waveform Modulationsare shifted by their respective frequency <strong>of</strong>fsets, pf . Shifting the n-th spectrum by2π pf /F s()()∣2π pfY n ω − = exp (− j2π f 0 t d ) exp (− j2π pft d )F ∣ X 2π pf ∣∣∣2ω −s F sand after reducing terms()(2π pfY n ω − = exp (− j2π f 0 t d )F ∣ X ω −sexp (− j (ωF s − 2π pf ) t d ) (2.69)2π pfF s)∣ ∣∣∣2exp (− jωF s t d ) (2.70)where (−π + 2π pf /F s ) ≤ ω ≤ (π + 2π pf /F s ). Note that the phase term 2πpft din equation (2.68) has been removed by the shifting operation. Its removal is necessary tocoherently combine the pulses. The match filtered and frequency shifted spectra containa constant phase term that is a function <strong>of</strong> f 0 and t d and a linear phase term proportionalto t d . The linear phase term positions the response in time after the inverse transform isapplied.The spectra in equation (2.70) are a result <strong>of</strong> applying the DTFT. To compute thespectra inside a signal processor, the DFT is applied. The K -length DFT is constructedby sampling the spectrum in equation (2.70) at ω k = 2πk/K , −K /2 ≤ k ≤ K/2 − 1 toyieldY n(2π k K−2π pfF s)(= exp (− j2π f 0 t d )∣ X 2π k K)∣2π pf ∣∣∣2− exp(− j2π k )F s K F st d(2.71)To align the pulse spectra, the frequency step size must be an integer multiple <strong>of</strong> the DFTbin size. The size <strong>of</strong> a DFT bin is found by computingδ f DFT = F sKThe frequency step size, f , is therefore constrained to be(2.72)f = Pδ f DFT (2.73)where P is an integer. Substituting equations (2.72) and (2.73) into equation (2.71)(Y n 2π k )(pP− 2π = exp (− j2π f 0 t d )K K∣ X 2π k )∣pP ∣∣∣2− 2π exp(− j2π k )K KK F st d(2.74)where (−K/2 + pP) ≤ k ≤ (K/2 − 1 + pP). Shifting the spectra has increased theK + (N sc − 1) Psize <strong>of</strong> the DFT to K + (N sc − 1) P, and the effective sample rate is F s .KZero padding may be applied in the frequency domain to force a power <strong>of</strong> 2 size FFT orto further interpolate the match filtered time-domain response.At this point, the spectra have been shifted, and a matched filter has been appliedto each pulse. The next step is to properly stitch together the shifted spectra to form acomposite spectrum that achieves the desired main lobe and sidelobe response when theinverse transform is applied. The stitching process is illustrated in Figure 2-9 using three

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!