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Mathematical Methods for Physics and Engineering - Matematica.NET

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14.4 EXERCISES(c) Find an appropriate integrating factor to obtainx = ln p − p + c ,(1 − p) 2which, together with the expression <strong>for</strong> y obtained in (a), gives a parameterisationof the solution.(d) Reverse the roles of x <strong>and</strong> y in steps (a) to (c), putting dx/dy = p −1 ,<strong>and</strong>show that essentially the same parameterisation is obtained.14.21 Using the substitutions u = x 2 <strong>and</strong> v = y 2 , reduce the equation( ) 2 dyxy − (x 2 + y 2 − 1) dy + xy =0dxdxto Clairaut’s <strong>for</strong>m. Hence show that the equation represents a family of conics<strong>and</strong> the four sides of a square.14.22 The action of the control mechanism on a particular system <strong>for</strong> an input f(t) isdescribed, <strong>for</strong> t ≥ 0, by the coupled first-order equations:ẏ +4z = f(t),ż − 2z = ẏ + 1 y. 2Use Laplace trans<strong>for</strong>ms to find the response y(t) of the system to a unit stepinput, f(t) =H(t), given that y(0) = 1 <strong>and</strong> z(0) = 0.Questions 23 to 31 are intended to give the reader practice in choosing an appropriatemethod. The level of difficulty varies within the set; if necessary, the hints maybe consulted <strong>for</strong> an indication of the most appropriate approach.14.23 Find the general solutions of the following:(a)dydx + xya 2 + x = x; dy(b) 2 dx = 4y2x − 2 y2 .14.24 Solve the following first-order equations <strong>for</strong> the boundary conditions given:(a) y ′ − (y/x) =1, y(1) = −1;(b) y ′ − y tan x =1, y(π/4) = 3;(c) y ′ − y 2 /x 2 =1/4, y(1) = 1;(d) y ′ − y 2 /x 2 =1/4, y(1) = 1/2.14.25 An electronic system has two inputs, to each of which a constant unit signal isapplied, but starting at different times. The equations governing the system thustake the <strong>for</strong>mẋ +2y = H(t),ẏ − 2x = H(t − 3).Initially (at t =0),x =1<strong>and</strong>y = 0; find x(t) atlatertimes.14.26 Solve the differential equationsin x dy +2y cos x =1,dxsubject to the boundary condition y(π/2) = 1.14.27 Find the complete solution of( ) 2 dy− y dydx x dx + A x =0,where A is a positive constant.487

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