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Mathematical Methods for Physics and Engineering - Matematica.NET

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SPECIAL FUNCTIONS18.9.1 Properties of Hermite polynomialsThe Hermite polynomials <strong>and</strong> functions derived from them are important in theanalysis of the quantum mechanical behaviour of some physical systems. Wethere<strong>for</strong>e briefly outline their useful properties in this section.Rodrigues’ <strong>for</strong>mulaThe Rodrigues’ <strong>for</strong>mula <strong>for</strong> the Hermite polynomials is given byH n (x) =(−1) n e x2dx n (e−x2 ). (18.130)This can be proved using Leibnitz’ theorem.◮Prove the Rodrigues’ <strong>for</strong>mula (18.130) <strong>for</strong> the Hermite polynomials.Letting u = e −x2 <strong>and</strong> differentiating with respect to x, we quickly find thatu ′ +2xu =0.Differentiating this equation n + 1 times using Leibnitz’ theorem then givesu (n+2) +2xu (n+1) +2(n +1)u (n) =0,which, on introducing the new variable v =(−1) n u (n) , reduces tov ′′ +2xv ′ +2(n +1)v =0. (18.131)Now letting y = e x2 v, we may write the derivatives of v asv ′ = e −x2 (y ′ − 2xy),v ′′ = e −x2 (y ′′ − 4xy ′ +4x 2 y − 2y).Substituting these expressions into (18.131), <strong>and</strong> dividing through by e −x2 , finally yieldsHermite’s equation,y ′′ − 2xy +2ny =0,thus demonstrating that y =(−1) n e x2 d n (e −x2 )/dx n is indeed a solution. Moreover, sincethis solution is clearly a polynomial of order n, it must be some multiple of H n (x). Thenormalisation is easily checked by noting that, from (18.130), the highest-order term is(2x) n , which agrees with the expression (18.128). ◭Mutual orthogonalityWe saw in section 17.4 that Hermite’s equation could be cast in Sturm–Liouville<strong>for</strong>m with p = e −x2 , q =0,λ =2n <strong>and</strong> ρ = e −x2 , <strong>and</strong> its natural interval is thus[−∞, ∞]. Since the Hermite polynomials H n (x) are solutions of the equation <strong>and</strong>are regular at the end-points, they must be mutually orthogonal over this intervalwith respect to the weight function ρ = e −x2 ,i.e.∫ ∞−∞dnH n (x)H k (x)e −x2 dx =0 ifn ≠ k.This result may also be proved directly using the Rodrigues’ <strong>for</strong>mula (18.130).Indeed, the normalisation, when k = n, is most easily found in this way.626

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