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Mathematical Methods for Physics and Engineering - Matematica.NET

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SERIES SOLUTIONS OF ORDINARY DIFFERENTIAL EQUATIONSwhere y 1 (x) <strong>and</strong>y 2 (x) arelinearly independent solutions of (16.1), <strong>and</strong> c 1 <strong>and</strong> c 2are constants that are fixed by the boundary conditions (if supplied).A full discussion of the linear independence of sets of functions was givenat the beginning of the previous chapter, but <strong>for</strong> just two functions y 1 <strong>and</strong> y 2to be linearly independent we simply require that y 2 is not a multiple of y 1 .Equivalently, y 1 <strong>and</strong> y 2 must be such that the equationc 1 y 1 (x)+c 2 y 2 (x) =0is only satisfied <strong>for</strong> c 1 = c 2 = 0. There<strong>for</strong>e the linear independence of y 1 (x) <strong>and</strong>y 2 (x) can usually be deduced by inspection but in any case can always be verifiedby the evaluation of the Wronskian of the two solutions,W (x) =∣ y 1 y 2y 1 ′ y 2′ ∣ = y 1y 2 ′ − y 2 y 1. ′ (16.3)If W (x) ≠ 0 anywhere in a given interval then y 1 <strong>and</strong> y 2 are linearly independentin that interval.An alternative expression <strong>for</strong> W (x), of which we will make use later, may bederived by differentiating (16.3) with respect to x to giveW ′ = y 1 y 2 ′′ + y 1y ′ 2 ′ − y 2 y 1 ′′ − y 2y ′ 1 ′ = y 1 y 2 ′′ − y 1y ′′2 .Since both y 1 <strong>and</strong> y 2 satisfy (16.1), we may substitute <strong>for</strong> y 1 ′′ <strong>and</strong> y′′ 2 to obtainW ′ = −y 1 (py 2 ′ + qy 2 )+(py 1 ′ + qy 1 )y 2 = −p(y 1 y 2 ′ − y 1y ′ 2 )=−pW .Integrating, we find{ ∫ x}W (x) =C exp − p(u) du , (16.4)where C is a constant. We note further that in the special case p(x) ≡ 0weobtainW =constant.◮The functions y 1 =sinx <strong>and</strong> y 2 =cosx are both solutions of the equation y ′′ + y =0. Evaluate the Wronskian of these two solutions, <strong>and</strong> hence show that they are linearlyindependent.The Wronskian of y 1 <strong>and</strong> y 2 is given byW = y 1 y 2 ′ − y 2 y 1 ′ = − sin 2 x − cos 2 x = −1.Since W ≠ 0 the two solutions are linearly independent. We also note that y ′′ + y =0isa special case of (16.1) with p(x) = 0. We there<strong>for</strong>e expect, from (16.4), that W will be aconstant, as is indeed the case. ◭From the previous chapter we recall that, once we have obtained the generalsolution to the homogeneous second-order ODE (16.1) in the <strong>for</strong>m (16.2), thegeneral solution to the inhomogeneous equationy ′′ + p(x)y ′ + q(x)y = f(x) (16.5)532

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