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Mathematical Methods for Physics and Engineering - Matematica.NET

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29.12 EXERCISESUse this to show that the character of the rotation in a representation based onthe orbital wavefunctions is given by1+2cosφ ′ +2cos2φ ′<strong>and</strong> hence that the characters of the representation, in the order of the symbolsgiven in exercise 29.5, is 5, −1, 1, −1, 1. Deduce that the five-fold degeneratelevel is split into two levels, a doublet <strong>and</strong> a triplet.29.8 Sulphur hexafluoride is a molecule with the same structure as the crystallinecompound in exercise 29.7, except that a sulphur atom is now the central atom.The following are the <strong>for</strong>ms of some of the electronic orbitals of the sulphuratom, together with the irreps according to which they trans<strong>for</strong>m under thesymmetry group 432 (or O).Ψ s = f(r) A 1Ψ p1 = zf(r) T 1Ψ d1 =(3z 2 − r 2 )f(r) EΨ d2 =(x 2 − y 2 )f(r) EΨ d3 = xyf(r) T 2The function x trans<strong>for</strong>ms according to the irrep T 1 . Use the above data todetermine whether dipole matrix elements of the <strong>for</strong>m J = ∫ φ 1 xφ 2 dτ can benon-zero <strong>for</strong> the following pairs of orbitals φ 1 ,φ 2 in a sulphur hexafluoridemolecule: (a) Ψ d1 , Ψ s ;(b)Ψ d1 , Ψ p1 ;(c)Ψ d2 , Ψ d1 ;(d)Ψ s , Ψ d3 ;(e)Ψ p1 , Ψ s .29.9 The hydrogen atoms in a methane molecule CH 4 <strong>for</strong>m a perfect tetrahedronwith the carbon atom at its centre. The molecule is most conveniently describedmathematically by placing the hydrogen atoms at the points (1, 1, 1), (1, −1, −1),(−1, 1, −1) <strong>and</strong> (−1, −1, 1). The symmetry group to which it belongs, the tetrahedralgroup (¯43m or T d ),hasclassestypifiedbyI, 3,2 z , m d <strong>and</strong> ¯4 z , where the firstthree are as in exercise 29.5, m d is a reflection in the mirror plane x − y =0<strong>and</strong>¯4 z is a rotation of π/2 about the z-axis followed by an inversion in the origin. Areflection in a mirror plane can be considered as a rotation of π about an axisperpendicular to the plane, followed by an inversion in the origin.Thecharactertable<strong>for</strong>thegroup¯43m is very similar to that <strong>for</strong> the group432, <strong>and</strong> has the <strong>for</strong>m shown in table 29.9.Typical element <strong>and</strong> class size Functions trans<strong>for</strong>mingIrreps I 3 2 z¯4z m d according to irrep1 8 3 6 6A 1 1 1 1 1 1 x 2 + y 2 + z 2A 2 1 1 1 −1 −1E 2 −1 2 0 0 (x 2 − y 2 , 3z 2 − r 2 )T 1 3 0 −1 1 −1 (R x ,R y ,R z )T 2 3 0 −1 −1 1 (x, y, z); (xy, yz, zx)Table 29.9The character table <strong>for</strong> group ¯43m.By following the steps given below, determine how many different internal vibrationfrequencies the CH 4 molecule has.(a) Consider a representation based on the twelve coordinates x i ,y i ,z i <strong>for</strong>i =1, 2, 3, 4. For those hydrogen atoms that trans<strong>for</strong>m into themselves, arotation through an angle θ about an axis parallel to one of the coordinateaxes gives rise in the natural representation to the diagonal elements 1 <strong>for</strong>1115

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