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Mathematical Methods for Physics and Engineering - Matematica.NET

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NORMAL MODESfrequency corresponds to a solution where the string <strong>and</strong> rod are moving withopposite phase <strong>and</strong> x 1 : x 2 =9.359 : −16.718. The two situations are shown infigure 9.1.In connection with quadratic <strong>for</strong>ms it was shown in section 8.17 how to makea change of coordinates such that the matrix <strong>for</strong> a particular <strong>for</strong>m becomesdiagonal. In exercise 9.6 a method is developed <strong>for</strong> diagonalising simultaneouslytwo quadratic <strong>for</strong>ms (though the trans<strong>for</strong>mation matrix may not be orthogonal).If this process is carried out <strong>for</strong> A <strong>and</strong> B in a general system undergoing stableoscillations, the kinetic <strong>and</strong> potential energies in the new variables η i take the<strong>for</strong>msT = ∑ iV = ∑ iµ i˙η 2 i = ˙η T M˙η, M = diag (µ 1 ,µ 2 ,...,µ N ), (9.11)ν i η 2 i = η T Nη, N = diag (ν 1 ,ν 2 ...,ν N ), (9.12)<strong>and</strong> the equations of motion are the uncoupled equationsµ i¨η i + ν i η i =0, i =1, 2,...,N. (9.13)Clearly a simple renormalisation of the η i can be made that reduces all the µ iin (9.11) to unity. When this is done the variables so <strong>for</strong>med are called normalcoordinates <strong>and</strong> equations (9.13) the normal equations.When a system is executing one of these simple harmonic motions it is said tobe in a normal mode, <strong>and</strong> once started in such a mode it will repeat its motionexactly after each interval of 2π/ω i . Any arbitrary motion of the system maybe written as a superposition of the normal modes, <strong>and</strong> each component modewill execute harmonic motion with the corresponding eigenfrequency; however,unless by chance the eigenfrequencies are in integer relationship, the system willnever return to its initial configuration after any finite time interval.As a second example we will consider a number of masses coupled together bysprings. For this type of situation the potential <strong>and</strong> kinetic energies are automaticallyquadratic functions of the coordinates <strong>and</strong> their derivatives, provided theelastic limits of the springs are not exceeded, <strong>and</strong> the oscillations do not have tobe vanishingly small <strong>for</strong> the analysis to be valid.◮Find the normal frequencies <strong>and</strong> modes of oscillation of three particles of masses m, µm,m connected in that order in a straight line by two equal light springs of <strong>for</strong>ce constant k.This arrangement could serve as a model <strong>for</strong> some linear molecules, e.g. CO 2 .The situation is shown in figure 9.2; the coordinates of the particles, x 1 , x 2 , x 3 , aremeasured from their equilibrium positions, at which the springs are neither extended norcompressed.The kinetic energy of the system is simplyT = 1 m ( ẋ 2 2 1 + µ ẋ 2 2 + ẋ3) 2 ,320

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