13.07.2015 Views

Mathematical Methods for Physics and Engineering - Matematica.NET

Mathematical Methods for Physics and Engineering - Matematica.NET

Mathematical Methods for Physics and Engineering - Matematica.NET

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

9.4 EXERCISESthe figure <strong>and</strong> obtain three linear equations governing the currents I 1 , I 2 <strong>and</strong> I 3 .Show that the only possible frequencies of self-sustaining currents satisfy eitherPCI 1QLULSI 2 TI 3CCR(a) ω 2 LC =1or(b)3ω 2 LC = 1. Find the corresponding current patterns <strong>and</strong>,in each case, by identifying parts of the circuit in which no current flows, drawan equivalent circuit that contains only one capacitor <strong>and</strong> one inductor.9.6 The simultaneous reduction to diagonal <strong>for</strong>m of two real symmetric quadratic <strong>for</strong>ms.Consider the two real symmetric quadratic <strong>for</strong>ms u T Au <strong>and</strong> u T Bu, whereu Tst<strong>and</strong>s <strong>for</strong> the row matrix (x y z), <strong>and</strong> denote by u n those column matricesthat satisfyBu n = λ n Au n ,(E9.1)in which n is a label <strong>and</strong> the λ n are real, non-zero <strong>and</strong> all different.(a) By multiplying (E9.1) on the left by (u m ) T , <strong>and</strong> the transpose of the correspondingequation <strong>for</strong> u m on the right by u n , show that (u m ) T Au n =0<strong>for</strong>n ≠ m.(b) By noting that Au n =(λ n ) −1 Bu n , deduce that (u m ) T Bu n =0<strong>for</strong>m ≠ n.(c) It can be shown that the u n are linearly independent; the next step is toconstruct a matrix P whose columns are the vectors u n .(d) Make a change of variables u = Pv such that u T Au becomes v T Cv, <strong>and</strong>u T Bubecomes v T Dv. Show that C <strong>and</strong> D are diagonal by showing that c ij =0ifi ≠ j, <strong>and</strong> similarly <strong>for</strong> d ij .Thus u = Pv or v = P −1 u reduces both quadratics to diagonal <strong>for</strong>m.To summarise, the method is as follows:(a) find the λ n that allow (E9.1) a non-zero solution, by solving |B − λA| =0;(b) <strong>for</strong> each λ n construct u n ;(c) construct the non-singular matrix P whose columns are the vectors u n ;(d) make the change of variable u = Pv.9.7 (It is recommended that the reader does not attempt this question until exercise 9.6has been studied.)If, in the pendulum system studied in section 9.1, the string is replaced by asecond rod identical to the first then the expressions <strong>for</strong> the kinetic energy T <strong>and</strong>the potential energy V become(tosecondorderintheθ i )T ≈ Ml ( 2 8 ˙θ 2 3 1 +2˙θ 1˙θ2 + 2 ˙θ 2 3 2),V ≈ Mgl ( 32 θ2 1 + 1 2 2) θ2 .Determine the normal frequencies of the system <strong>and</strong> find new variables ξ <strong>and</strong> ηthat will reduce these two expressions to diagonal <strong>for</strong>m, i.e. toa 1˙ξ2 + a 2˙η 2 <strong>and</strong> b 1 ξ 2 + b 2 η 2 .331

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!