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Mathematical Methods for Physics and Engineering - Matematica.NET

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SERIES SOLUTIONS OF ORDINARY DIFFERENTIAL EQUATIONScoefficient of the highest power z N ; such a power now exists because of ourassumed <strong>for</strong>m of solution.◮By assuming a polynomial solution find the values of λ in (16.34) <strong>for</strong> which such a solutionexists.We assume a polynomial solution to (16.34) of the <strong>for</strong>m y = ∑ Nn=0 a nz n . Substituting this<strong>for</strong>m into (16.34) we findN∑ [n(n − 1)an z n−2 − 2zna n z n−1 + λa n z n] =0.n=0Now, instead of starting with the lowest power of z, we start with the highest. Thus,dem<strong>and</strong>ing that the coefficient of z N vanishes, we require −2N + λ =0,i.e.λ =2N, aswefound in the previous example. By dem<strong>and</strong>ing that the coefficient of a general power of zis zero, the same recurrence relation as above may be derived <strong>and</strong> the solutions found. ◭16.6 Exercises16.1 Find two power series solutions about z = 0 of the differential equation(1 − z 2 )y ′′ − 3zy ′ + λy =0.Deduce that the value of λ <strong>for</strong> which the corresponding power series becomes anNth-degree polynomial U N (z) isN(N + 2). Construct U 2 (z) <strong>and</strong>U 3 (z).16.2 Find solutions, as power series in z, of the equation4zy ′′ +2(1− z)y ′ − y =0.Identify one of the solutions <strong>and</strong> verify it by direct substitution.16.3 Find power series solutions in z of the differential equationzy ′′ − 2y ′ +9z 5 y =0.Identify closed <strong>for</strong>ms <strong>for</strong> the two series, calculate their Wronskian, <strong>and</strong> verifythat they are linearly independent. Compare the Wronskian with that calculatedfrom the differential equation.16.4 Change the independent variable in the equationd 2 f df+2(z − a) +4f =0dz2 dz (∗)from z to x = z − α, <strong>and</strong> find two independent series solutions, exp<strong>and</strong>ed aboutx = 0, of the resulting equation. Deduce that the general solution of (∗) is∞∑ (−4) m m!f(z,α) =A(z − α)e −(z−α)2 + B(z − α) 2m ,(2m)!m=0with A <strong>and</strong> B arbitrary constants.16.5 Investigate solutions of Legendre’s equation at one of its singular points asfollows.(a) Verify that z = 1 is a regular singular point of Legendre’s equation <strong>and</strong> thatthe indicial equation <strong>for</strong> a series solution in powers of (z − 1) has roots 0<strong>and</strong> 3.(b) Obtain the corresponding recurrence relation <strong>and</strong> show that σ = 0 does notgive a valid series solution.550

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