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Mathematical Methods for Physics and Engineering - Matematica.NET

Mathematical Methods for Physics and Engineering - Matematica.NET

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VECTOR CALCULUSThere<strong>for</strong>e, remembering that u = x, from (10.12) the arc length between x = a <strong>and</strong> x = bis given by∫ b√ √drs =a du · dr ∫ b( ) 2 dydu du = 1+ dx.a dxThis result was derived using more elementary methods in chapter 2. ◭If a curve C is described by r(u) then, by considering figures 10.1 <strong>and</strong> 10.3, wesee that, at any given point on the curve, dr/du is a vector tangent to C at thatpoint, in the direction of increasing u. In the special case where the parameter uis the arc length s along the curve then dr/ds is a unit tangent vector to C <strong>and</strong> isdenoted by ˆt.The rate at which the unit tangent ˆt changes with respect to s is given byd ˆt/ds, <strong>and</strong> its magnitude is defined as the curvature κ of the curve C at a givenpoint,∣ ∣ κ =d ˆt∣∣∣ ∣ ds ∣ = d 2 ˆr ∣∣∣ds 2 .We can also define the quantity ρ =1/κ, which is called the radius of curvature.Since ˆt is of constant (unit) magnitude, it follows from (10.8) that it is perpendicularto d ˆt/ds. The unit vector in the direction perpendicular to ˆt is denotedby ˆn <strong>and</strong> is called the principal normal at the point. We there<strong>for</strong>e haved ˆt= κ ˆn. (10.13)dsThe unit vector ˆb = ˆt × ˆn, which is perpendicular to the plane containing ˆt<strong>and</strong> ˆn, is called the binormal to C. The vectors ˆt, ˆn <strong>and</strong> ˆb <strong>for</strong>m a right-h<strong>and</strong>edrectangular cooordinate system (or triad) at any given point on C (see figure 10.3).As s changes so that the point of interest moves along C, the triad of vectors alsochanges.The rate at which ˆb changes with respect to s is given by d ˆb/ds <strong>and</strong> is ameasure of the torsion τ of the curve at any given point. Since ˆb is of constantmagnitude, from (10.8) it is perpendicular to d ˆb/ds. We may further show thatd ˆb/ds is also perpendicular to ˆt, as follows. By definition ˆb · ˆt =0,whichondifferentiating yields0= d ( )ˆb · ˆt = d ˆbds ds · ˆt + ˆb · d ˆtds= d ˆbds · ˆt + ˆb · κ ˆn= d ˆbds · ˆt,where we have used the fact that ˆb · ˆn = 0. Hence, since d ˆb/ds is perpendicularto both ˆb <strong>and</strong> ˆt, we must have d ˆb/ds ∝ ˆn. The constant of proportionality is −τ,342

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