13.07.2015 Views

Mathematical Methods for Physics and Engineering - Matematica.NET

Mathematical Methods for Physics and Engineering - Matematica.NET

Mathematical Methods for Physics and Engineering - Matematica.NET

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

STATISTICSHowever, since the sample values x i are assumed to be independent, we haveE[x r i x r j]=E[x r i ]E[x r j]=µ 2 r . (31.52)The number of terms in the sum on the RHS of (31.51) is N(N −1), <strong>and</strong> so we findV [m r ]= 1 N µ 2r − µ 2 r + N − 1Nµ2 r = µ 2r − µ 2 rN . (31.53)Since E[m r ]=µ r <strong>and</strong> V [m r ] → 0asN →∞,therth sample moment m r is alsoa consistent estimator of µ r .◮Find the covariance of the sample moments m r <strong>and</strong> m s <strong>for</strong> a sample of size N.We obtain the covariance of the sample moments m r <strong>and</strong> m s in a similar manner to thatused above to obtain the variance of m r . From the definition of covariance, we haveCov[m r ,m s ]=E[(m r − µ r )(m s − µ s )][( )( )]= 1 ∑ ∑N E x r 2 i − Nµ r x s j − Nµ sij= 1 N 2 E ⎡⎣ ∑ ix r+si+ ∑ i⎤∑∑ ∑x r i x s j − Nµ r x s j − Nµ s x r i + N 2 µ r µ s⎦Assuming the x i to be independent, we may again use result (31.52) to obtainj≠iCov[m r ,m s ]= 1 N [Nµ 2 r+s + N(N − 1)µ r µ s − N 2 µ r µ s − N 2 µ s µ r + N 2 µ r µ s ]= 1 N µ r+s + N − 1Nµ rµ s − µ r µ s= µ r+s − µ r µ s.NWe note that by setting r = s, we recover the expression (31.53) <strong>for</strong> V [m r ]. ◭ji31.4.5 Population central moments ν rWe may generalise the discussion of estimators <strong>for</strong> the second central moment ν 2(or equivalently σ 2 ) given in subsection 31.4.2 to the estimation of the rth centralmoment ν r . In particular, we saw in that subsection that our choice of estimator<strong>for</strong> ν 2 depended on whether the population mean µ 1 is known; the same is true<strong>for</strong> the estimation of ν r .Let us first consider the case in which µ 1 is known. From (30.54), we may writeν r asν r = µ r − r C 1 µ r−1 µ 1 + ···+(−1) k r C k µ r−k µ k 1 + ···+(−1) r−1 ( r C r−1 − 1)µ r 1.If µ 1 is known, a suitable estimator is obviouslyˆν r = m r − r C 1 m r−1 µ 1 + ···+(−1) k r C k m r−k µ k 1 + ···+(−1) r−1 ( r C r−1 − 1)µ r 1,where m r is the rth sample moment. Since µ 1 <strong>and</strong> the binomial coefficients are1250

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!