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Mathematical Methods for Physics and Engineering - Matematica.NET

Mathematical Methods for Physics and Engineering - Matematica.NET

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2.2 INTEGRATIONCombining (2.23) <strong>and</strong> (2.24) with c set equal to a shows that∫ bf(x) dx = −∫ aabf(x) dx. (2.26)2.2.2 Integration as the inverse of differentiationThe definite integral has been defined as the area under a curve between twofixed limits. Let us now consider the integralF(x) =∫ xaf(u) du (2.27)in which the lower limit a remains fixed but the upper limit x is now variable. Itwill be noticed that this is essentially a restatement of (2.21), but that the variablex in the integr<strong>and</strong> has been replaced by a new variable u. It is conventional torename the dummy variable in the integr<strong>and</strong> in this way in order that the samevariable does not appear in both the integr<strong>and</strong> <strong>and</strong> the integration limits.It is apparent from (2.27) that F(x) is a continuous function of x, but at firstglance the definition of an integral as the area under a curve does not connect withour assertion that integration is the inverse process to differentiation. However,by considering the integral (2.27) <strong>and</strong> using the elementary property (2.24), weobtainF(x +∆x) ==∫ x+∆xa∫ xa= F(x)+f(u) duf(u) du +x∫ x+∆xRearranging <strong>and</strong> dividing through by ∆x yieldsF(x +∆x) − F(x)∆xx= 1∆x∫ x+∆xf(u) du.∫ x+∆xxf(u) duf(u) du.Letting ∆x → 0 <strong>and</strong> using (2.1) we find that the LHS becomes dF/dx, whereasthe RHS becomes f(x). The latter conclusion follows because when ∆x is smallthe value of the integral on the RHS is approximately f(x)∆x, <strong>and</strong> in the limit∆x → 0 no approximation is involved. ThusdF(x)= f(x), (2.28)dxor, substituting <strong>for</strong> F(x) from (2.27),[∫d x]f(u) du = f(x).dxa61

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