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Mathematical Methods for Physics and Engineering - Matematica.NET

Mathematical Methods for Physics and Engineering - Matematica.NET

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PDES: SEPARATION OF VARIABLES AND OTHER METHODSWe may treat the diffusion equationκ∇ 2 u = ∂u∂tin a similar way. Separating the spatial <strong>and</strong> time dependences by assuming asolution of the <strong>for</strong>m u = F(r)T (t), <strong>and</strong> taking the separation constant as k 2 ,wefind∇ 2 F + k 2 dTF =0,dt + k2 κT =0.Just as in the case of the wave equation, the spatial part of the solution satisfiesHelmholtz’s equation. It only remains to consider the time dependence, whichhas the simple solutionT (t) =A exp(−k 2 κt).Helmholtz’s equation is clearly of central importance in the solutions of thewave <strong>and</strong> diffusion equations. It can be solved in polar coordinates in much thesame way as Laplace’s equation, <strong>and</strong> indeed reduces to Laplace’s equation whenk = 0. There<strong>for</strong>e, we will merely sketch the method of its solution in each of thethree polar coordinate systems.Helmholtz’s equation in plane polarsIn two-dimensional plane polar coordinates, Helmholtz’s equation takes the <strong>for</strong>m(1 ∂ρ ∂F )+ 1 ∂ 2 Fρ ∂ρ ∂ρ ρ 2 ∂φ 2 + k2 F =0.If we try a separated solution of the <strong>for</strong>m F(r) = P (ρ)Φ(φ), <strong>and</strong> take theseparation constant as m 2 , we findd 2 Φdφ 2 + m2 φ =0,d 2 Pdρ 2 + 1 ( )dPρ dρ + k 2 − m2ρ 2 P =0.As <strong>for</strong> Laplace’s equation, the angular part has the familiar solution (if m ≠0)Φ(φ) =A cos mφ + B sin mφ,or an equivalent <strong>for</strong>m in terms of complex exponentials. The radial equationdiffers from that found in the solution of Laplace’s equation, but by making thesubstitution µ = kρ it is easily trans<strong>for</strong>med into Bessel’s equation of order m(discussed in chapter 16), <strong>and</strong> has the solutionP (ρ) =CJ m (kρ)+DY m (kρ),where Y m is a Bessel function of the second kind, which is infinite at the origin738

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