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Mathematical Methods for Physics and Engineering - Matematica.NET

Mathematical Methods for Physics and Engineering - Matematica.NET

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STATISTICSSuppose, we wish to estimate the value of one of the quantities a 1 ,a 2 ,...,whichwe will denote simply by a. Since the sample values x i provide our only source ofin<strong>for</strong>mation, any estimate of a must be some function of the x i , i.e. some samplestatistic. Such a statistic is called an estimator of a <strong>and</strong> is usually denoted by â(x),where x denotes the sample elements x 1 ,x 2 ,...,x N .Since an estimator â is a function of the sample values of the r<strong>and</strong>om variablesx 1 ,x 2 ,...,x N , it too must be a r<strong>and</strong>om variable. In other words, if a number ofr<strong>and</strong>om samples, each of the same size N, are taken from the (one-dimensional)population P (x|a) then the value of the estimator â will vary from one sample tothe next <strong>and</strong> in general will not be equal to the true value a. This variation in theestimator is described by its sampling distribution P (â|a). From section 30.14, thisis given byP (â|a) dâ = P (x|a) d N x,where d N x is the infinitesimal ‘volume’ in x-space lying between the ‘surfaces’â(x) =â <strong>and</strong> â(x) =â + dâ. The <strong>for</strong>m of the sampling distribution generallydepends upon the estimator under consideration <strong>and</strong> upon the <strong>for</strong>m of thepopulation from which the sample was drawn, including, as indicated, the truevalues of the quantities a. It is also usually dependent on the sample size N.◮The sample values x 1 ,x 2 ,...,x N are drawn independently from a Gaussian distributionwith mean µ <strong>and</strong> variance σ. Suppose that we choose the sample mean ¯x as our estimatorˆµ of the population mean. Find the sampling distributions of this estimator.The sample mean ¯x is given by¯x = 1 N (x 1 + x 2 + ···+ x N ),where the x i are independent r<strong>and</strong>om variables distributed as x i ∼ N(µ, σ 2 ). From ourdiscussion of multiple Gaussian distributions on page 1189, we see immediately that ¯x willalso be Gaussian distributed as N(µ, σ 2 /N). In other words, the sampling distribution of¯x is given byP (¯x|µ, σ) =[1√2πσ2 /N exp −Note that the variance of this distribution is σ 2 /N. ◭](¯x − µ)2. (31.13)2σ 2 /N31.3.1 Consistency, bias <strong>and</strong> efficiency of estimatorsFor any particular quantity a, we may in fact define any number of differentestimators, each of which will have its own sampling distribution. The qualityof a given estimator â may be assessed by investigating certain properties of itssampling distribution P (â|a). In particular, an estimator â is usually judged onthe three criteria of consistency, bias <strong>and</strong> efficiency, each of which we now discuss.1230

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