Adaptative high-gain extended Kalman filter and applications
Adaptative high-gain extended Kalman filter and applications
Adaptative high-gain extended Kalman filter and applications
Create successful ePaper yourself
Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.
tel-00559107, version 1 - 24 Jan 2011<br />
5.2 Continuous-discrete Framework<br />
As in Section 3.5, we need to write the prediction-correction Riccati equations in a different<br />
time scale (τ), so that we can bound the Riccati matrix independently from θ. We consider<br />
dτ = θ(t)dt or equivalently τ = � t<br />
0 θ(v)dv <strong>and</strong> keep the notation ¯x(τ) = ˜x(t).<br />
⎧<br />
⎨ d<br />
⎩<br />
¯ �<br />
S<br />
dτ = − A(u)+ ˜b ∗ �′ �<br />
(z,u)<br />
S − S A(u)+<br />
θ<br />
˜b ∗ �<br />
(z,u)<br />
− SQS<br />
θ<br />
¯Sk(+) = ¯ Sk(−)+θδtC ′<br />
r−1 (5.38)<br />
C.<br />
Since θ(t) varies within an interval of the form [1, θmax], the instants tk = kδt, k ∈ N are<br />
difficult to track in the τ time scale. For convenience, tk = kδt is denoted τk in the τ time<br />
scale.<br />
With the help of this representation we are able to derive the following lemma:<br />
Lemma 66<br />
Let us consider the prediction correction Riccati equations (5.38), <strong>and</strong> the assumptions:<br />
�<br />
�<br />
− the functions ai (u (t)), �˜b ∗ i,j (z,u)<br />
�<br />
�<br />
�, are smaller than aM > 0,<br />
− ai (u (t)) ≥ am > 0, i =2, ..., n,<br />
− θ(0) = 1, <strong>and</strong><br />
− S(0) is a symmetric positive definite matrix taken from a compact subset of the form<br />
aId ≤ S(0) ≤ bId.<br />
Then, there exists a constant µ, <strong>and</strong> two scalars 0 < α 0, <strong>and</strong> ε ∗ as in Theorem 62.<br />
Let us now set a time T such that 0 < T < T ∗ .<br />
Let α <strong>and</strong> β be the bounds of Lemma 66.<br />
For t ∈ [kδt;(k + 1)δt[, inequality (5.31) can be written (i.e. using αId ≤ ˜ S),<br />
d˜ε ′ ˜ S˜ε (t)<br />
dt<br />
≤−αqmθ˜ε ′ � �<br />
′<br />
S˜ε ˜ (t) + 2˜ε ˜S ˜b (˜z) − ˜b (˜x) − ˜∗ b (˜z)˜ε<br />
110<br />
(5.39)